A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have magnitudes F₁ = 0 kip, F₂ = 0 kip, and F3 = 30 kip. The truss is held in equilibrium by a pin at point A and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F lies s= 30 ft to the right and h = 10 ft above joint A, and joint C lies h = 10 ft above joint F. Use the method of joints to determine the force in each member of the truss, and indicate whether they are in tension or compression. Note: Express tension forces as positive (+) and compression forces as negative (-). A B S F₁ F₂ F C F3 D S E h h
A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have magnitudes F₁ = 0 kip, F₂ = 0 kip, and F3 = 30 kip. The truss is held in equilibrium by a pin at point A and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F lies s= 30 ft to the right and h = 10 ft above joint A, and joint C lies h = 10 ft above joint F. Use the method of joints to determine the force in each member of the truss, and indicate whether they are in tension or compression. Note: Express tension forces as positive (+) and compression forces as negative (-). A B S F₁ F₂ F C F3 D S E h h
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have
magnitudes F₁ = 0 kip, F₂ = 0 kip, and F3 = 30 kip. The truss is held in equilibrium by a pin at point A and
a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F
lies s =
30 ft to the right and h = 10 ft above joint A, and joint C lies h
method of joints to determine the force in each member of the truss, and indicate whether they are in
10 ft above joint F. Use the
tension or compression.
Note: Express tension forces as positive (+) and compression forces as negative (-).
A
S
B
F₂₁
F₂
2
F
LL
C
F₂
D
S
GENER
E 000
7777
휴
Th
h

Transcribed Image Text:PAB= -55.56
PAF =
PBC =
PBF= -31.62
PCD= -19.51
PCF=
PDE =
PDF=
PEF= 48.9
48.9
-19.51
0.
-55.56
-31.62
kip
kip
kip
kip
kip
kip
kip
kip
kip
? *0%
x 0%
X 0%
? × 0%
X0%
? X0%
x 0%
✓ 100%
? x 0%
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