A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces havemagnitudes F₁ = 0 kip, F₂ = 0 kip, and F3 = 30 kip. The truss is held in equilibrium by a pin at point A anda roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint Flies s =30 ft to the right and h = 10 ft above joint A, and joint C lies hmethod of joints to determine the force in each member of the truss, and indicate whether they are in10 ft above joint F. Use thetension or compression.Note: Express tension forces as positive (+) and compression forces as negative (-).ASBF₂₁F₂2FLLCF₂DSGENERE 0007777휴Thh PAB= -55.56PAF =PBC =PBF= -31.62PCD= -19.51PCF=PDE =PDF=PEF= 48.948.9-19.510.-55.56-31.62kipkipkipkipkipkipkipkipkip? *0%x 0%X 0%? × 0%X0%? X0%x 0%✓ 100%? x 0%

Given Data : F1=0 kip F2= 0 kip F3=30 kip S=30 ft h=10 ft

A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have magnitudes F₁ = 0 kip, F₂ = 0 kip, and F3 = 30 kip. The truss is held in equilibrium by a pin at point A and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F lies s= 30 ft to the right and h = 10 ft above joint A, and joint C lies h = 10 ft above joint F. Use the method of joints to determine the force in each member of the truss, and indicate whether they are in tension or compression. Note: Express tension forces as positive (+) and compression forces as negative (-). A B S F₁ F₂ F C F3 D S E h h

A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have magnitudes F₁ = 0 kip, F₂ = 0 kip, and F3 = 30 kip. The truss is held in equilibrium by a pin at point A and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F lies s= 30 ft to the right and h = 10 ft above joint A, and joint C lies h = 10 ft above joint F. Use the method of joints to determine the force in each member of the truss, and indicate whether they are in tension or compression. Note: Express tension forces as positive (+) and compression forces as negative (-). A B S F₁ F₂ F C F3 D S E h h

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Mechanics of Solids

It is the study of the behavior of solid materials, their characteristics under various circumstances such as variation in external forces, temperature, and other internal factors. It is one of most important study in the field of engineering science, especially chemistry and mechanical engineering. In rigid body, the idealization of the solid body in which deformation is neglected. Deformation is known as the force acting on the solid state system which exerts change in its shape of the body but it continues to be at rest or in a uniform motion but it cannot accelerate. But those solid systems do have elasticity, compressibility and can be bent. This field is very vast since there are wide range of materials around us.

Question

A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have
magnitudes F₁ = 0 kip, F₂ = 0 kip, and F3 = 30 kip. The truss is held in equilibrium by a pin at point A and
a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F
lies s =
30 ft to the right and h = 10 ft above joint A, and joint C lies h
method of joints to determine the force in each member of the truss, and indicate whether they are in
10 ft above joint F. Use the
tension or compression.
Note: Express tension forces as positive (+) and compression forces as negative (-).
A
S
B
F₂₁
F₂
2
F
LL
C
F₂
D
S
GENER
E 000
7777
휴
Th
h

PAB= -55.56
PAF =
PBC =
PBF= -31.62
PCD= -19.51
PCF=
PDE =
PDF=
PEF= 48.9
48.9
-19.51
0.
-55.56
-31.62
kip
kip
kip
kip
kip
kip
kip
kip
kip
? *0%
x 0%
X 0%
? × 0%
X0%
? X0%
x 0%
✓ 100%
? x 0%

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