Calculate all the member forces in the given truss using method of consistent deformation. Joint D is pinned supported and joint E is roller supported. F=4450 kN and L=8m. Take 'EA' same for all members В F 1 2 L 3 5 4 E

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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**Truss Member Forces Calculation: Method of Consistent Deformation**

This problem involves calculating the forces in each member of the given truss structure using the method of consistent deformation. The truss has different types of supports and members, and specific known values for the applied force and dimensions.

**Parameters:**
- Joint D: Pinned support
- Joint E: Roller support
- Force (F): 4450 kN
- Length (L): 8 meters
- Assume 'EA' (Elastic Modulus multiplied by Area) is the same for all members.

**Truss Configuration:**

The truss is a square with diagonal members intersecting at the center. The key components and members are labeled as follows:

- Vertices: B, C, D, and E.
- Applied horizontal force at point C labeled as 'F'.

**Members:**
1. BD (Diagonal)
2. CE (Diagonal)
3. DB (Vertical)
4. DE (Bottom Horizontal)
5. EC (Vertical)
6. BC (Top Horizontal)

**Diagram Breakdown:**

- The square formed by points B, C, D, and E has diagonal and horizontal members that need evaluation of forces.
- Point D is pinned, and point E has a roller support, implying constraints on movement at these points.
- The applied force 'F' acts horizontally at point C, introducing tensile or compressive forces in the members.

This configuration and method require using principles of structural analysis such as equilibrium equations, compatibility conditions, and material properties to solve for internal forces in each truss member.
Transcribed Image Text:**Truss Member Forces Calculation: Method of Consistent Deformation** This problem involves calculating the forces in each member of the given truss structure using the method of consistent deformation. The truss has different types of supports and members, and specific known values for the applied force and dimensions. **Parameters:** - Joint D: Pinned support - Joint E: Roller support - Force (F): 4450 kN - Length (L): 8 meters - Assume 'EA' (Elastic Modulus multiplied by Area) is the same for all members. **Truss Configuration:** The truss is a square with diagonal members intersecting at the center. The key components and members are labeled as follows: - Vertices: B, C, D, and E. - Applied horizontal force at point C labeled as 'F'. **Members:** 1. BD (Diagonal) 2. CE (Diagonal) 3. DB (Vertical) 4. DE (Bottom Horizontal) 5. EC (Vertical) 6. BC (Top Horizontal) **Diagram Breakdown:** - The square formed by points B, C, D, and E has diagonal and horizontal members that need evaluation of forces. - Point D is pinned, and point E has a roller support, implying constraints on movement at these points. - The applied force 'F' acts horizontally at point C, introducing tensile or compressive forces in the members. This configuration and method require using principles of structural analysis such as equilibrium equations, compatibility conditions, and material properties to solve for internal forces in each truss member.
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