The image shows a table with several entries representing forces in a structural system. Each row corresponds to a force between two points labeled alphabetically. The forces are expressed in 'kip,' which is a unit of force equivalent to 1,000 pounds-force (lbf). Each entry is meant to be substituted with a numerical value. The format provided for this substitution includes relative tolerance (rtol) and absolute tolerance (atol), which are parameters for the precision of numerical input.Here is the detailed transcription of each entry:- \( P_{AB} = \text{number (rtol=0.01, atol=1e-05)} \) kip- \( P_{AF} = \text{number (rtol=0.01, atol=1e-05)} \) kip- \( P_{BC} = \text{number (rtol=0.01, atol=1e-05)} \) kip- \( P_{BF} = \text{number (rtol=0.01, atol=1e-05)} \) kip- \( P_{CD} = \text{number (rtol=0.01, atol=1e-05)} \) kip- \( P_{CF} = \text{number (rtol=0.01, atol=1e-05)} \) kip- \( P_{DE} = \text{number (rtol=0.01, atol=1e-05)} \) kip- \( P_{DF} = \text{number (rtol=0.01, atol=1e-05)} \) kip- \( P_{EF} = \text{number (rtol=0.01, atol=1e-05)} \) kipEach force is associated with a question mark icon, which might be used for accessing additional information or help, though this is not explicitly described in the image. **Analyzing Forces in a Scissors Truss**A scissors truss supports three forces at joints B, C, and D, as shown in the accompanying diagram. The forces have magnitudes \( F_1 = 20 \, \text{kip} \), \( F_2 = 35 \, \text{kip} \), and \( F_3 = 45 \, \text{kip} \). The truss is held in equilibrium by a pin at point A and a roller at point E. It is important to note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical.- **Joint F**: Located \( s = 24 \, \text{ft} \) to the right of joint A and \( h = 8 \, \text{ft} \) above joint A.- **Joint C**: Located \( h = 8 \, \text{ft} \) above joint F.**Objective**: Using the method of joints, determine the force in each member of the truss and indicate whether they are in tension or compression.**Note**: Express tension forces as positive (+) and compression forces as negative (-).**Diagram Explanation**: The diagram illustrates the truss configuration and the distribution of forces:- Pins and rollers are represented at points A and E, providing support.- The forces \( F_1 \), \( F_2 \), and \( F_3 \) are shown as vertical arrows at joints B, C, and D respectively, indicating their direction (downward).- The dimensions \( s \) and \( h \) highlight the distances between specific joints horizontally and vertically, contributing to a clearer understanding of the structure's geometry.Understanding this setup is crucial for calculating and analyzing the forces acting within each member of the truss. By applying the method of joints, one can determine the internal forces and establish whether each member is in tension or compression.

Given: The magnitude of forces are given as: F1=20 kipF2=35 kipF3=45 kip The value of s is 24 ft and the value of h is 8 ft. To Determine: The forces in each member of the truss by using the method of joints and also indicate whether they are in tension or compression.Draw the free-body diagram of the given truss.

Engineering

Civil Engineering

A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have magnitudes F₁ = 20 kip, F₂ = 35 kip, and F3 = 45 kip. The truss is held in equilibrium by a pin at point A and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F lies s = 24 ft to the right and h = 8 ft above joint A, and joint C lies h = 8 ft above joint F. Use the method of joints to determine the force in each member of the truss, and indicate whether they are in tension or compression.

A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have magnitudes F₁ = 20 kip, F₂ = 35 kip, and F3 = 45 kip. The truss is held in equilibrium by a pin at point A and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F lies s = 24 ft to the right and h = 8 ft above joint A, and joint C lies h = 8 ft above joint F. Use the method of joints to determine the force in each member of the truss, and indicate whether they are in tension or compression.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Mechanics of Solids

It is the study of the behavior of solid materials, their characteristics under various circumstances such as variation in external forces, temperature, and other internal factors. It is one of most important study in the field of engineering science, especially chemistry and mechanical engineering. In rigid body, the idealization of the solid body in which deformation is neglected. Deformation is known as the force acting on the solid state system which exerts change in its shape of the body but it continues to be at rest or in a uniform motion but it cannot accelerate. But those solid systems do have elasticity, compressibility and can be bent. This field is very vast since there are wide range of materials around us.

Question

The image shows a table with several entries representing forces in a structural system. Each row corresponds to a force between two points labeled alphabetically. The forces are expressed in 'kip,' which is a unit of force equivalent to 1,000 pounds-force (lbf). Each entry is meant to be substituted with a numerical value. The format provided for this substitution includes relative tolerance (rtol) and absolute tolerance (atol), which are parameters for the precision of numerical input.

Here is the detailed transcription of each entry:

- \( P_{AB} = \text{number (rtol=0.01, atol=1e-05)} \) kip
- \( P_{AF} = \text{number (rtol=0.01, atol=1e-05)} \) kip
- \( P_{BC} = \text{number (rtol=0.01, atol=1e-05)} \) kip
- \( P_{BF} = \text{number (rtol=0.01, atol=1e-05)} \) kip
- \( P_{CD} = \text{number (rtol=0.01, atol=1e-05)} \) kip
- \( P_{CF} = \text{number (rtol=0.01, atol=1e-05)} \) kip
- \( P_{DE} = \text{number (rtol=0.01, atol=1e-05)} \) kip
- \( P_{DF} = \text{number (rtol=0.01, atol=1e-05)} \) kip
- \( P_{EF} = \text{number (rtol=0.01, atol=1e-05)} \) kip

Each force is associated with a question mark icon, which might be used for accessing additional information or help, though this is not explicitly described in the image.

**Analyzing Forces in a Scissors Truss**

A scissors truss supports three forces at joints B, C, and D, as shown in the accompanying diagram. The forces have magnitudes \( F_1 = 20 \, \text{kip} \), \( F_2 = 35 \, \text{kip} \), and \( F_3 = 45 \, \text{kip} \). The truss is held in equilibrium by a pin at point A and a roller at point E. It is important to note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical.

- **Joint F**: Located \( s = 24 \, \text{ft} \) to the right of joint A and \( h = 8 \, \text{ft} \) above joint A.
- **Joint C**: Located \( h = 8 \, \text{ft} \) above joint F.

**Objective**: Using the method of joints, determine the force in each member of the truss and indicate whether they are in tension or compression.

**Note**: Express tension forces as positive (+) and compression forces as negative (-).

**Diagram Explanation**:

The diagram illustrates the truss configuration and the distribution of forces:

- Pins and rollers are represented at points A and E, providing support.
- The forces \( F_1 \), \( F_2 \), and \( F_3 \) are shown as vertical arrows at joints B, C, and D respectively, indicating their direction (downward).
- The dimensions \( s \) and \( h \) highlight the distances between specific joints horizontally and vertically, contributing to a clearer understanding of the structure's geometry.

Understanding this setup is crucial for calculating and analyzing the forces acting within each member of the truss. By applying the method of joints, one can determine the internal forces and establish whether each member is in tension or compression.

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