A scheme of random number generator is described as follows. First, onegenerates a normal random number with mean 0 and variance 16, a uniform random numberon [0,24], then a geometric random number of parameter p = 0.25 (each independently).Then we define the random number to be the average of these three numbers. 30 randomnumbers are generated with the scheme above, denoted as {X}31. Estimate/approximatethe probability that the average 1 X is deviated from μ = E[X₁] by a distance of morethan 0.2 using: (a) Chebyshev's inequality; (b) central limit theorem.k=1

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A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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EXAMPLE 5a If the number of items produced in a factory during a week is a random variable with mean 100 and variance 400, compute an upper bound on the probability that this week's production will be at least 120.
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