A sample of an unknown peptide was divided into two aliquots. One aliquot was treated withtrypsin; the other was treated with cyanogen bromide. Given the following sequences (N-terminal to C-terminal) of the resulting fragments, deduce the sequence of the original peptide.Trypsin treatmentAsn-Thr-Trp-Met-Ile-LysGly-Tyr-Met-Gln–PheVal-Leu-GlyMet-Ser-ArgCyanogen bromide treatmentGln–PheVal-Leu-Gly-MetIle-Lys-Gly-Tyr-MetSer-Arg-Asn-Thr-Trp-Met

Cyanogen bromide hydrolyzes the peptide bonds at the C-terminus of methionine residues. Polypeptide…

Answered: A sample of an unknown peptide was…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Neurospora crassa can synthesize the amino acid arginine from a precursor as follows: precursor ornithine - citrulline arginine George Beadle and Edward Tatum identified various mutants (arg mutants) unable to synthesize arginine from this precursor. One such class (Class I) could synthesize arginine if either ornithine or citrulline was supplied. A second mutant class (Class II) could synthesize arginine if citrulline was added, but not if ornithine was added. A third class (Class II) could not synthesize arginine from either ornithine or citrulline. Which class or classes of arg mutants LACK a functional enzyme able to convert ornithine into citrulline?
Draw the structure of the following DNA sequence (5’-AG-3’) hydrogen bonded through Watson-Crick base pairing to the complementary PNA sequence (Cterminus-TC-Nterminus). Make sure to include both the sugar phosphate backbone of your DNA sequence, as well as the peptide backbone of your PNA sequence. DNA: 5’-AG-3’ PNA: (C)-TC-(N)
The complementarity of its two strands is the underlying reason that DNA can be faithfully copied. Propose alternative chemical structures that could be faithfully copied.
What are Okazaki fragments? Why are they formed?
There are different tRNAs for each amino acid. What is one major way to differentiate among the tRNAs for each amino acid?
The authors state: "Properties of the single mutants K557R, D591V and K617A, a double mutant, D591V/K617A, and a triple mutant, K557R/D591V/K617A, were evaluated to find an allosteric binding site for citrate." The numbers between the letters represent the residue number altered. The letter in front was the wild type and the letter afterwards is the mutant. How would the the triple mutations K557R and D591V and K617A alter the overall protein? O lower the # of charges, increase the pl O increase the # of charges, increase the pl O lower the # of charges, lower the pl O lower the # of charges, increase the pl O no change in the # of charges, increase the pl O no change in the # of charges, lower the pl
Position on the small and large ribosomal subunits which the peptidyl-tRNA occupies prior to peptide bond formation Group of answer choices a)No answer text provided. b)A Site c)P Site
Southern blotting is a method used in molecular biology for detection of a specific DNA sequence in DNA samples while northern blotting is used for the detection of RNA in a sample. Write down the similarities and differences between both methods.
Amino acid compositions can be determined by heating a protein in 6 M HCl and running the hydrolysate through an ionexchange column. If you were going to do an amino acid sequencing experiment, why would you want to get an amino acid composition first?
A DNA fragment was sequenced; however, the scatter-brained professor lost track of the direction of the sequence. The resulting sequence is given, but without the 3’ or 5’ ends identified. NOTE the sequence listed is double stranded. (a) Find all START codons (in both directions and for both strands) and report the sequence of the two start codon(s) plus the next 3 bases downstream (i.e. 5’ to 3’ direction). (b) One of the start codons has a STOP codon 6 codons downstream, list the 21 bases that contain the target sequence and 7 amino acids that this (very short) open reading frame would translate to. (c) Identify the 3’ or 5’ ends for lables1- 4.

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A sample of an unknown peptide was divided into two aliquots. One aliquot was treated with trypsin; the other was treated with cyanogen bromide. Given the following sequences (N- terminal to C-terminal) of the resulting fragments, deduce the sequence of the original peptide.