A sample of 1500 computer chips revealed that 26% of the chips fail in the first 1000 hours of their use. The company's promotional literature claimed that 29% fail in the first 1000 hours of their use. Is there sufficient evidence at the 0.05 level to dispute the company's claim? State the null and alternative hypotheses for the above scenario.
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- A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 77%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 77% of married couples. In a random sample of 250 married couples who completed her program, 194 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor's claim at the 0.10 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) (a) State the null hypothesis H and the alternative hypothesis H₁. H₁:0 H₁ :0 (b) Determine the type of test statistic to use. (Choose one) (c) Find the value of the test statistic. (Round to three or more decimal places.) 0 (d) Find the p-value. (Round to three or more decimal places.) 0 (e) Is there enough…If the 95% confidence interval contains zero (more precisely, the parameter value specified in the null hypothesis), then what will be the effect at the 0.05 level?The business college wants to determine the proportion of business students who have extended time between classes. If the proportion differs from 30%, then the lab will modify a proposed enlargement of its facilities. Suppose a hypothesis test is conducted and the test statistic is 2.5. Find the P-value for a two-tailed test of hypothesis.
- A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 80%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 80% of married couples. In a random sample of 215 married couples who completed her program, 180 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor’s claim at the 0.05 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. A. State the null hypothesis Hoand the alternative hypothesis H1. Ho: H1: B. Find the value of the test statistic. (Round to three or more decimal places.) C. Find the critical value. (Round to three or more decimal places.) D. Is there enough evidence to support the marriage counselor's claim that the proportion of married couples for whom her program…Previously, 3% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 3% today. She randomly selects 145 pregnant mothers and finds that 3 of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the a = 0.1 level of significance. What are the null and alternative hypotheses? Họ: P = 0.03 versus H4: p < 0.03 (Type integers or decimals. Do not round.) Because npo (1- Po) =|| 10, the normal model V be used to approximate the P-value. (Round to one decimal place as needed.)A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 79%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 79% of married couples. In a random sample of 250 married couples who completed her program, 205 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor's claim at the 0.05 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) (a) State the null hypothesis H and the alternative hypothesis H₁. H₂ : D H₁ : 0 (b) Determine the type of test statistic to use. (Choose one) (c) Find the value of the test statistic. (Round to three or more decimal places.) 0 (d) Find the p-value. (Round to three or more decimal places.) 0 (e) Is there enough…
- A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 77%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 77% of married couples. In a random sample of 215 married couples who completed her program, 167 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor’s claim at the 0.10 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) (a) State the null hypothesis H0 and the alternative hypothesis H1. H0: H1: (b) Determine the type of test statistic to use. ▼(Choose one) (c) Find the value of the test statistic. (Round to three or more decimal places.) (d) Find the p-value. (Round to three…An experimenter has prepared a drug-dose level that he claims will induce sleep for at least 70% of people suffering from insomnia. After examining the dosage we feel that his claims regarding the effectiveness of his dosage are too high. In an attempt to disprove his claim, we administer his prescribed dosage to 80 insomniacs and observe that 51 of them have had sleep induced by the drug dose. Is there enough evidence to refute his claim at the 5% level of significance? a) state null and alternate hypotheses b) find the test statistic and rejection region c) state your conclusionLooking at youth depression scores from a general sample of random children in the US, we want to determine if our sample is significantly different than the national average of scores of children with depression in the US. The national average of scores on a measure of depression is 5 points. We have no reason to assume it will be higher or lower than the US national average. The sample: 11 9 12 3 3 4 13 1. What is the null and alternative hypotheses? Do not specify any directionality. 2. What did you discover (using 95% Cl)? Provide an interpretation.
- A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 78%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 78% of married couples. In a random sample of 240 married couples who completed her program, 189 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor’s claim at the 0.10 level of significance?Perform a one-tailed test. Then complete the parts below.A hospital director believes that above 55% of the lab reports contain errors and feels an audit is required. A sample of 120 reports found 72 errors. Is there sufficient evidence at the 0.02 level to substantiate the hospital director's claim? State the null and alternative hypotheses for the above scenario.1. An insurance company states that 70% of its claims are settled within 60 days. A consumer group selected a random sample of 85 of the company's claims to test this statement. If the consumer group found that 65 of the claims were settled within 60 days, do they have sufficient reason to support their contention that fewer than 70% of the claims are settled within 60 days? Use 5% level of significance. Step 1: State the hypotheses. Step 2: The level of significance, one/two-tailed test, degrees of freedom Step 3: Statistical Test Step 4: Computation Step 5: Decision Rule Step 6: Reject Ho or Failed to Reject Ho Step 7: Conclusion