A salt sample was analyzed for its purity. A 0.5000 g sample was dissolved in water and diluted to 250 mL. From this solution, 25.00 mL was taken for analysis. To this aliquot, 20.00 mL of a 0.08735 M AgNO3 solution was added to precipitate the chloride. The excess AgNO3 required 12.45 mL of a 0.09473 M KSCN solution for back-titration. Calculate the purity of the salt sample as percent by mass of KCl (74.55 g/mol)
A salt sample was analyzed for its purity. A 0.5000 g sample was dissolved in water and diluted to 250 mL. From this solution, 25.00 mL was taken for analysis. To this aliquot, 20.00 mL of a 0.08735 M AgNO3 solution was added to precipitate the chloride. The excess AgNO3 required 12.45 mL of a 0.09473 M KSCN solution for back-titration. Calculate the purity of the salt sample as percent by mass of KCl (74.55 g/mol)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A salt sample was analyzed for its purity. A 0.5000 g sample was dissolved in water and diluted to 250 mL. From this solution, 25.00 mL was taken for analysis. To this aliquot, 20.00 mL of a 0.08735 M AgNO3 solution was added to precipitate the chloride. The excess AgNO3 required 12.45 mL of a 0.09473 M KSCN solution for back-titration. Calculate the purity of the salt sample as percent by mass of KCl (74.55 g/mol)
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