A ring-shaped conductor with radius a = 2.20 cm has a total positive charge Q = 0.122 nC uniformly distributed around it. (Figure 1) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Field of a ring of charge. Figure dQ ds X dE, dE La 1 of 1 dE x What is the magnitude of the electric field at point P, which is on the positive x-axis at x = 45.0 cm ? Express your answer in newtons per coulomb. [ΠΙ ΑΣΦ E= Submit Request Answer Part B What is the direction of the electric field at point P? O+x-direction O-x-direction Submit Request Answer ? N/C

College Physics
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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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Please solve the problem in the pictures

A ring-shaped conductor with radius a = 2.20 cm has a
total positive charge Q = 0.122 nC uniformly distributed
around it. (Figure 1)
For related problem-solving tips and strategies, you may
want to view a Video Tutor Solution of
Field of a ring of charge.
Figure
e
a
0
dQ
ds
√x² + a²
X
dEy
dE
1 of 1
dE
X
▼
Part A
What is the magnitude of the electric field at point P, which is on the positive x-axis at x = 45.0 cm ?
Express your answer in newtons per coulomb.
IV—| ΑΣΦ
E =
Submit
Part B
Request Answer
What is the direction of the electric field at point P?
+x-direction
-x-direction
Submit
Request Answer
?
N/C
Transcribed Image Text:A ring-shaped conductor with radius a = 2.20 cm has a total positive charge Q = 0.122 nC uniformly distributed around it. (Figure 1) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Field of a ring of charge. Figure e a 0 dQ ds √x² + a² X dEy dE 1 of 1 dE X ▼ Part A What is the magnitude of the electric field at point P, which is on the positive x-axis at x = 45.0 cm ? Express your answer in newtons per coulomb. IV—| ΑΣΦ E = Submit Part B Request Answer What is the direction of the electric field at point P? +x-direction -x-direction Submit Request Answer ? N/C
Part C
A particle with a charge of 3.00 μC is placed at the point P described in part A. What is the magnitude of the force
exerted by the particle on the ring?
Express your answer in newtons.
F =
IVE ΑΣΦ
Submit Request Answer
Part D
+x-direction
What is the direction of the force exerted by the particle on the ring?
-x-direction
Submit
Request Answer
?
P Pearson
N
Review | Constants
Transcribed Image Text:Part C A particle with a charge of 3.00 μC is placed at the point P described in part A. What is the magnitude of the force exerted by the particle on the ring? Express your answer in newtons. F = IVE ΑΣΦ Submit Request Answer Part D +x-direction What is the direction of the force exerted by the particle on the ring? -x-direction Submit Request Answer ? P Pearson N Review | Constants
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