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19. A child on a sled (m = 47.0 kg) slides down a long hill starting from a rest position at a point 10.0 m higher in elevation than his finishing point. a) What is the total mechanical energy present? b) Assuming that there is no friction and no external pushes, determine the child's speed at the bottom of the hill. c) The child's speed at the bottom of the hill is actually 5.0 m/s. Explain whether or not this defies the law of conservation of energy.

19. A child on a sled (m = 47.0 kg) slides down a long hill starting from a rest position at a point 10.0 m higher in elevation than his finishing point. a) What is the total mechanical energy present? b) Assuming that there is no friction and no external pushes, determine the child's speed at the bottom of the hill. c) The child's speed at the bottom of the hill is actually 5.0 m/s. Explain whether or not this defies the law of conservation of energy.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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use guess method while doing the answer if u cant use guess method then i prefer u not doing it at all

Example A car is accelerating from 80 m/s to 120 m/s in 8 seconds. Calculate the acceleration? G: v₁ = 80m/s vf = 120m/s At = 8s U: a =? 21 E: a = 5 120-80 S m S: a = 8s for acceleration As you can see, I carried the unit of measure for speed and time in the formula S: a = 120-80m 8s the units for measure for acceleration. I know there is 8s² m 40™ = 40 = 40÷8s = 40 × ² = 8s m indeed the units for measure for acceleration is 40m m = = 5 As you can see here, I calculated but I show my work and prove that I hope that my example is clear. If you have any questions please write an email.
Transcribed Image Text:Example A car is accelerating from 80 m/s to 120 m/s in 8 seconds. Calculate the acceleration? G: v₁ = 80m/s vf = 120m/s At = 8s U: a =? 21 E: a = 5 120-80 S m S: a = 8s for acceleration As you can see, I carried the unit of measure for speed and time in the formula S: a = 120-80m 8s the units for measure for acceleration. I know there is 8s² m 40™ = 40 = 40÷8s = 40 × ² = 8s m indeed the units for measure for acceleration is 40m m = = 5 As you can see here, I calculated but I show my work and prove that I hope that my example is clear. If you have any questions please write an email.
19. A child on a sled (m = 47.0 kg) slides down a long hill starting from a rest position at a point 10.0 m higher in elevation than his finishing point. a) What is the total mechanical energy present? b) Assuming that there is no friction and no external pushes, determine the child's speed at the bottom of the hill. c) The child's speed at the bottom of the hill is actually 5.0 m/s. Explain whether or not this defies the law of conservation of energy.
Transcribed Image Text:19. A child on a sled (m = 47.0 kg) slides down a long hill starting from a rest position at a point 10.0 m higher in elevation than his finishing point. a) What is the total mechanical energy present? b) Assuming that there is no friction and no external pushes, determine the child's speed at the bottom of the hill. c) The child's speed at the bottom of the hill is actually 5.0 m/s. Explain whether or not this defies the law of conservation of energy.
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