11. (II) Particles of charge +65, +48, and -95 µC are placed in a line (Fig. 16-52). The center one is 0.35 m from each of the others. Calculate the net force on each charge due to the other two. +65 MC +48 μC -95 μC 0.35 m 0.35 m FIGURE 16-52 Problem 11.
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An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.
please type out your solution so that it is easy to read I have bad eyesight and cant read handwriting well please type do not handwrite
![### Physics Problem on Electrostatic Forces (Educational Website Content)
#### Problem 11
**(II)** Particles of charge \( +65 \, \mu C \), \( +48 \, \mu C \), and \( -95 \, \mu C \) are placed in a line (Fig. 16-52). The center one is \( 0.35 \, \text{m} \) from each of the others. Calculate the net force on each charge due to the other two.
![Diagram depicting charges](image-url)
**Explanation of Figure 16-52:**
The given figure (Figure 16-52, Problem 11) illustrates three charged particles arranged in a linear configuration. The three charges are:
- A \( +65 \, \mu C \) charge (represented by a red dot) on the left.
- A \( +48 \, \mu C \) charge (also represented by a red dot) in the center.
- A \( -95 \, \mu C \) charge (represented by a green dot) on the right.
Each charge is located \( 0.35 \, \text{m} \) away from its neighboring charges. The distances in the diagram are labeled as follows:
- Distance between the \( +65 \, \mu C \) charge and the \( +48 \, \mu C \) charge is \( 0.35 \, \text{m} \).
- Distance between the \( +48 \, \mu C \) charge and the \( -95 \, \mu C \) charge is \( 0.35 \, \text{m} \).
### Objective
The goal is to calculate the net force acting on each of the charges due to the electric forces exerted by the other two charges.
**Illustrative Note:**
Electric forces between two charges can be calculated using Coulomb's Law:
\[ F = k_e \frac{|q_1 q_2|}{r^2} \]
where:
- \( F \) is the magnitude of the force between the charges.
- \( k_e \) is Coulomb's constant (\(8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2\)).
- \( q_1 \) and \( q_2 \) are the](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F22536c29-fcc1-4871-92e0-85fb58db97f7%2Fe5f6e1e1-dafa-4357-a08b-13cb52e2d7d4%2F5vv9qm_processed.png&w=3840&q=75)
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