A right triangle has side lengths 8, 15, and 17 as shown below. Use these lengths to find sin X, tan X, and cosX. X 15 za 8 17 sin X = tan X = cos X= 0 8 08 EEE D U Aal Aa
A right triangle has side lengths 8, 15, and 17 as shown below. Use these lengths to find sin X, tan X, and cosX. X 15 za 8 17 sin X = tan X = cos X= 0 8 08 EEE D U Aal Aa
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter1: Line And Angle Relationships
Section1.2: Angles And Their Relationships
Problem 37E: Draw a triangle with three acute angles. Construct angle bisectors for each of the three angles. On...
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![## Understanding Trigonometric Ratios in a Right Triangle
A **right triangle** has side lengths \(8, 15, \) and \(17\) as shown below. Use these lengths to find \(\sin X\), \(\tan X\), and \(\cos X\).
### Diagram Explanation
The right triangle is labeled with vertices \(X\), \(Y\), and \(Z\), where \(\angle Z\) is the right angle.
- The side opposite \(\angle X\) (denoted as \(YZ\)) is \(8\) units.
- The side adjacent to \(\angle X\) (denoted as \(ZX\)) is \(15\) units.
- The hypotenuse \(XY\) is \(17\) units.
### Calculation of Trigonometric Ratios
To find the trigonometric ratios (sine, tangent, and cosine) for \(\angle X\), we use the following definitions:
- \(\sin X = \frac{\text{opposite}}{\text{hypotenuse}}\)
- \(\tan X = \frac{\text{opposite}}{\text{adjacent}}\)
- \(\cos X = \frac{\text{adjacent}}{\text{hypotenuse}}\)
1. **Sine (\(\sin X\))**:
\[
\sin X = \frac{8}{17}
\]
2. **Tangent (\(\tan X\))**:
\[
\tan X = \frac{8}{15}
\]
3. **Cosine (\(\cos X\))**:
\[
\cos X = \frac{15}{17}
\]
### Summary
This problem demonstrates how to use the side lengths of a right triangle to calculate the primary trigonometric ratios for one of its angles.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcd1ff857-92ff-4e51-81f6-c8581968700f%2F1d90913f-e877-476a-b220-78196156544e%2Fx61rngh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:## Understanding Trigonometric Ratios in a Right Triangle
A **right triangle** has side lengths \(8, 15, \) and \(17\) as shown below. Use these lengths to find \(\sin X\), \(\tan X\), and \(\cos X\).
### Diagram Explanation
The right triangle is labeled with vertices \(X\), \(Y\), and \(Z\), where \(\angle Z\) is the right angle.
- The side opposite \(\angle X\) (denoted as \(YZ\)) is \(8\) units.
- The side adjacent to \(\angle X\) (denoted as \(ZX\)) is \(15\) units.
- The hypotenuse \(XY\) is \(17\) units.
### Calculation of Trigonometric Ratios
To find the trigonometric ratios (sine, tangent, and cosine) for \(\angle X\), we use the following definitions:
- \(\sin X = \frac{\text{opposite}}{\text{hypotenuse}}\)
- \(\tan X = \frac{\text{opposite}}{\text{adjacent}}\)
- \(\cos X = \frac{\text{adjacent}}{\text{hypotenuse}}\)
1. **Sine (\(\sin X\))**:
\[
\sin X = \frac{8}{17}
\]
2. **Tangent (\(\tan X\))**:
\[
\tan X = \frac{8}{15}
\]
3. **Cosine (\(\cos X\))**:
\[
\cos X = \frac{15}{17}
\]
### Summary
This problem demonstrates how to use the side lengths of a right triangle to calculate the primary trigonometric ratios for one of its angles.
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