47 ### Geometry Problems#### Problem 46: Find the area of this trapezoidGiven a trapezoid with bases \( b_1 = 9 \text{ft} \) and \( b_2 = 7 \text{ft} \), and a height \( h = 11 \text{ft} \), use the formula for the area of a trapezoid:\[ A = \frac{1}{2} h (b_1 + b_2) \]- A. 70 ft²- B. 88 ft²- C. 77 ft²- D. 81 ft²The diagram provided shows a trapezoid with its bases and height labeled for clarity.#### Problem 47: Find the similarity ratio of two triangles with areas 16 ft² and 49 ft²Given the areas of two triangles, 16 ft² and 49 ft², find their similarity ratio.- A. 256 : 2401- B. 8 : 24.5- C. 2 : 3.5- D. 4 : 7 The answer choices provide various ratios for comparison. Note: The similarity ratio is found by taking the square root of the ratio of the areas.

46.Accordin to the diagram, h= 11 ft , b1=9 ft and b2 = 7 ftThe area of the trapezium…

46. Find the area of this trapezoid using A=2(b + b₂). 9 ft A. 70 ft² B. 88 ft² C. 77 ft² D. 81 ft² 11 ft 7 ft CR & auibe bas 47. Find the similarity ratio of two triangles with areas 16 ft² and 49 ft². A. 256 : 2401 B. 8:24.5 C. 2:3.5 D. 4:7