A resistor with resistance R and a capacitor with capacitance Care connected in series to an AC voltage source. The time-dependent voltage across the capacitor is given by Vc (t) = Vc, sin wt. Part A What is the amplitude Io of the total current I (t) in the circuit? Express your answer in terms of any or all of R, C, Vc, and w. ► View Available Hint(s) PA [Π ΑΣΦ α V Л Δ Σ Io = Vc wc Y P 8 Y € Ꮎ T Φ Ω ħ E X K W @ X ? μ

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**Educational Content: Analyzing an AC Circuit with a Resistor and Capacitor**

**Concept Overview:**

In an AC (Alternating Current) circuit, a resistor with resistance \( R \) and a capacitor with capacitance \( C \) can be connected in series to an AC voltage source. The voltage across the capacitor is a time-dependent function, described by:

\[ V_C(t) = V_0 \sin(\omega t) \]

where:
- \( V_0 \) is the peak voltage,
- \( \omega \) is the angular frequency,
- \( t \) represents time.

**Problem Statement:**

*Part A: Determining the Amplitude of Current*

The task is to find the amplitude \( I_0 \) of the total current \( I(t) \) in the circuit. The variables available for expressing the answer are \( R \), \( C \), \( V_0 \), and \( \omega \).

**Proposed Solution Approach:**

The current expression provided was:

\[ I_0 = V_{C_0} \omega C \]

Upon submission, it was noted that this answer is incorrect and does not rely on \( V_0 \omega C \). Students are encouraged to revisit the relationship and formula derivations considering both capacitive and resistive contributions to current.

**Submission Feedback:**

After entering the equation, feedback indicates "Incorrect; Try Again," with 3 attempts remaining. This suggests reevaluating the dependent variables and how they affect the amplitude of the current.
Transcribed Image Text:**Educational Content: Analyzing an AC Circuit with a Resistor and Capacitor** **Concept Overview:** In an AC (Alternating Current) circuit, a resistor with resistance \( R \) and a capacitor with capacitance \( C \) can be connected in series to an AC voltage source. The voltage across the capacitor is a time-dependent function, described by: \[ V_C(t) = V_0 \sin(\omega t) \] where: - \( V_0 \) is the peak voltage, - \( \omega \) is the angular frequency, - \( t \) represents time. **Problem Statement:** *Part A: Determining the Amplitude of Current* The task is to find the amplitude \( I_0 \) of the total current \( I(t) \) in the circuit. The variables available for expressing the answer are \( R \), \( C \), \( V_0 \), and \( \omega \). **Proposed Solution Approach:** The current expression provided was: \[ I_0 = V_{C_0} \omega C \] Upon submission, it was noted that this answer is incorrect and does not rely on \( V_0 \omega C \). Students are encouraged to revisit the relationship and formula derivations considering both capacitive and resistive contributions to current. **Submission Feedback:** After entering the equation, feedback indicates "Incorrect; Try Again," with 3 attempts remaining. This suggests reevaluating the dependent variables and how they affect the amplitude of the current.
Expert Solution
Step 1: Total current in RC circuit

In a series circuit with a resistor and a capacitor connected to an AC voltage source, the total current I not stretchy left parenthesis t not stretchy right parenthesis can be expressed as:

I left parenthesis t right parenthesis equals fraction numerator V subscript C subscript 0 end subscript over denominator square root of R squared plus left parenthesis fraction numerator 1 over denominator omega C end fraction right parenthesis squared end root end fraction space sin space left parenthesis omega t plus ϕ right parenthesis

Where:
V subscript C subscript 0 end subscript is the amplitude of the voltage across the capacitor,
R is the resistance,
C is the capacitance,
omega is the angular frequency of the AC source,
ϕ is the phase angle between the current and voltage.


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