a through b please Consider the circuit diagram in the figure. Part (a) What is the equation which results when applying the loop rule to loop aedcba, in terms of the variables given in the figure? O= _____ Part (b) If the current through the middle part of the loop is I1 = 4.75 amps, what is the current through the top loop, I2, in amps? I2= ______

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Chapter1: Units, Trigonometry. And Vectors
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a through b please

Consider the circuit diagram in the figure.

Part (a) What is the equation which results when applying the loop rule to loop aedcba, in terms of the variables given in the figure?

O= _____

Part (b) If the current through the middle part of the loop is I1 = 4.75 amps, what is the current through the top loop, I2, in amps?

I2= ______

R₂
2.5 Ω·
a
€1=18V
1₁
E=45 V
Μ
R₁
0.5 Ω
12
ww
0.5 Ω
R₂
[1.5 Ω
Transcribed Image Text:R₂ 2.5 Ω· a €1=18V 1₁ E=45 V Μ R₁ 0.5 Ω 12 ww 0.5 Ω R₂ [1.5 Ω
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