Consider the circuit shown in (Figure 1). Suppose that E = 11 V. Figure 20 Ω 60 Ω www LuwLiw Switch 1 of 1 40 Ω 10 Ω ▼ Part A What is the current through the battery when the switch is open? Express your answer with the appropriate units. μA H I = Value Units Submit Request Answer Part B What is the current through the battery when the switch is closed? Express your answer with the appropriate units. ΜΑ ? I = Value Units Submit Request Answer

Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Paul W. Zitzewitz
Chapter23: Series And Parallel Circuits
Section23.1: Simple Circuits
Problem 24SSC
icon
Related questions
Question
### Circuit Analysis Problem

#### Problem Statement:
Consider the circuit shown in **Figure 1**. Suppose that \( \mathcal{E} = 11 \, \text{V} \).

#### Diagram:
![Figure 1: Circuit Diagram](circuit_image.jpg)
- **Figure 1** shows a circuit with a voltage source (\( \mathcal{E} \)) of \( 11 \, \text{V} \).
- The circuit contains four resistors with the following resistances: \( 20 \, \Omega \), \( 40 \, \Omega \), \( 60 \, \Omega \), and \( 10 \, \Omega \).
- A switch is present in the circuit, connected such that it is in series with the \( 10 \, \Omega \) resistor and in parallel with the \( 40 \, \Omega \) resistor.

#### Questions:

**Part A:**
- What is the current through the battery when the switch is open?
- **Express your answer with the appropriate units.**

Input box for answer:
\[ I = \]
\[ \text{Value } \text{Units} \]

Submit Button: [Submit]

Request Answer Link: [Request Answer]

---

**Part B:**
- What is the current through the battery when the switch is closed?
- **Express your answer with the appropriate units.**

Input box for answer:
\[ I = \]
\[ \text{Value } \text{Units} \]

Submit Button: [Submit]

Request Answer Link: [Request Answer] 

---

### Explanation of Diagram:
**Figure 1** illustrates the configuration of the resistors within the circuit, clearly showing the position of the switch. When analyzing the circuit, consider the following:
- **Switch Open:** The \( 10 \, \Omega \) resistor is not part of the circuit path, and current flows only through the \( 20 \, \Omega \), \( 40 \, \Omega \), and \( 60 \, \Omega \) resistors.
- **Switch Closed:** The \( 10 \, \Omega \) resistor is added in parallel to the \( 40 \, \Omega \) resistor, changing the circuit's overall resistance and the current distribution.

Use Ohm’s Law ( \( V = IR \) ) and the rules for series and parallel circuits to determine the total resistance and the current.
Transcribed Image Text:### Circuit Analysis Problem #### Problem Statement: Consider the circuit shown in **Figure 1**. Suppose that \( \mathcal{E} = 11 \, \text{V} \). #### Diagram: ![Figure 1: Circuit Diagram](circuit_image.jpg) - **Figure 1** shows a circuit with a voltage source (\( \mathcal{E} \)) of \( 11 \, \text{V} \). - The circuit contains four resistors with the following resistances: \( 20 \, \Omega \), \( 40 \, \Omega \), \( 60 \, \Omega \), and \( 10 \, \Omega \). - A switch is present in the circuit, connected such that it is in series with the \( 10 \, \Omega \) resistor and in parallel with the \( 40 \, \Omega \) resistor. #### Questions: **Part A:** - What is the current through the battery when the switch is open? - **Express your answer with the appropriate units.** Input box for answer: \[ I = \] \[ \text{Value } \text{Units} \] Submit Button: [Submit] Request Answer Link: [Request Answer] --- **Part B:** - What is the current through the battery when the switch is closed? - **Express your answer with the appropriate units.** Input box for answer: \[ I = \] \[ \text{Value } \text{Units} \] Submit Button: [Submit] Request Answer Link: [Request Answer] --- ### Explanation of Diagram: **Figure 1** illustrates the configuration of the resistors within the circuit, clearly showing the position of the switch. When analyzing the circuit, consider the following: - **Switch Open:** The \( 10 \, \Omega \) resistor is not part of the circuit path, and current flows only through the \( 20 \, \Omega \), \( 40 \, \Omega \), and \( 60 \, \Omega \) resistors. - **Switch Closed:** The \( 10 \, \Omega \) resistor is added in parallel to the \( 40 \, \Omega \) resistor, changing the circuit's overall resistance and the current distribution. Use Ohm’s Law ( \( V = IR \) ) and the rules for series and parallel circuits to determine the total resistance and the current.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 3 images

Blurred answer
Knowledge Booster
DC circuits
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Glencoe Physics: Principles and Problems, Student…
Glencoe Physics: Principles and Problems, Student…
Physics
ISBN:
9780078807213
Author:
Paul W. Zitzewitz
Publisher:
Glencoe/McGraw-Hill
Inquiry into Physics
Inquiry into Physics
Physics
ISBN:
9781337515863
Author:
Ostdiek
Publisher:
Cengage
College Physics
College Physics
Physics
ISBN:
9781938168000
Author:
Paul Peter Urone, Roger Hinrichs
Publisher:
OpenStax College