(d) H₁P₁ P₂P, = P.Ps vs H₁: ₁ ₂ 3(2) Consider the following Minitab ANOVA output. Fill in the missing values. Round yoAnalysis of VarianceDFAdj MSSourceTempAdj SS127.625263.81Error120.802Total14137.249(3) Can you conclude that the mean strength differs with temperature? Select one right answer:a. The test statistic (F-value) < F-critical, reject HO. Mean strength differs with temperature.b. The test statistic (F-value) < F-critical, do not reject HO. Mean strength differs with temperature.c. The test statistic (F-value) > F-critical, do not reject HO. Mean strength differs with temperature.d. The test statistic (F-value) > F-critical, reject HO. Mean strength differs with temperature.Moving to another question will save this response Question 5A research laboratory is studying the effect of temperature or the compressive strength oeach of three temperatures, and the compressive strength of each specimen is measured. ThTemperature1531.235.929.636.8203038.337.0(1) Select the right hypothesis to test the mean strength differs with temperature:(a) H0₁=₂=₁3vs H.: At least two means differ(b) ₁:₁ =₂=₂ = P₁ = Psvs H.: At least two means differvs H.:(c) H₁: P₁ P₂ P3₂3(d) ₁:₁ =₂=₂=₁=Ps vs H₁: ₁*. *..(2) Consider the following Minitab ANOVA output. Fill in the missing values. Round your a

For the given data Perform Anova one way

Answered: A research laboratory is studying the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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can you please help me solve sub-parts e, f, g
Past research has indicated that the average age of death row inmates is 41 years old. researcher would like to determine if the average age has changed. She randomly selects 50 death row inma s and ds their average age to be 37 years old. The hypothesis the statistician wants to test is: a. Ho: µ=37 vs_ Ha: µ ± 41. b. Ho: µ=41 vs Ha: µ< 41. Ho: u = 41 vs. H: u 41 d. Ho: µ=37 vs_Ha: µ< 41. C. 2. If a player at a casino is playing roulette and betting on red, there is a 18 / 38 or 0.474 chance that he will win on any spin of the roulette wheel. If we take a random sample of 300 players betting on red, then p is the proportion of times that the player wins. What is the mean of the sampling distribution of p? t' a. b. What is the standard deviation (os) of the sampling distribution of p? c. If repeated samples of 300 players are taken, what would be the range of the sample proportion of players victories according to the 95 part of the 68-95-99.7 rule" pts) 3. The z statistic for a…
Given below are the ages and heart rates of 50 patents aho participated in a dinical tral for a new ant-hypertersive drug A a Graphicaly, what can you conclude about the relationship between age and heart rate? B. b. Test the hypothesis that p= 0 against the altemative that p0 at the 0.05 level of significance| Heart Rate (y) 100 76 Patient No. Age Patient No. Age Heart Rate 1 48 26 39 72 2 45 27 56 70 3 67 70 28 51 76 4 44 72 29 41 68 57 62 64 30 31 32 49 76 70 79 92 72 70 76 53 58 60 62 33 67 76 47 34 54 68 37 76 86 10 84 35 49 11 52 90 36 54 12 66 90 37 44 81 13 33 80 38 69 72 14 30 68 39 45 80 15 41 72 40 39 80 16 52 74 41 37 72 17 40 30 76 42 45 52 86 18 88 43 72 19 35 84 44 44 76 20 49 70 45 28 39 76 21 62 51 72 68 46 74 68 22 47 49 72 23 41 76 48 80 24 55 70 49 52 80 25 63 68 s0 27 82
Answers: 1.a) rXY = 0.461, t = 1.272, Do not reject H0: no evidence for a significant correlation between the two variables b) 43.66
10. An engineering study was undertaken to determine the optimum thickness of aluminum to be used to construct cans to be used for cat food. Cans made of aluminum of thickness 2.10 mm and 1.90 mm were tested to determine the maximum load each would sustain before collapsing. The sample data is summarized below. Use a = 0.05 to test the claim that the thicker cans are stronger (will withstand a higher load). 2.10 mm thick 1.90 mm thick sample size 175 170 mean maximum load (kg) 28.18 26.71 standard deviation of maximum load (kg) | 2.78 2.21
An experiment to compare the tension bond strength of polymer latex modified mortar (Portland cement mortar to which polymer latex emulsións have been added during mixing) to that of unmodified mortar resulted in x = 18.11 kgf/cm2 for the modified mortar (m = 42) and y = 16.88 kgf/cm2 for the unmodified mortar (n = 31). Let ₁ and ₂ be the true average tension bond strengths for the modified and unmodified mortars, respectively. Assume that the bond strength distributions are both normal. (a) Assuming that o₁ = 1.6 and ₂ = 1.3, test Ho: ₁ - ₂ = 0 versus H₂: H₁ - H₂> 0 at level 0.01. Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) Z = P-value = State the conclusion in the problem context. O Fail to reject Ho. The data suggests that the difference in average tension bond strengths exceeds 0. Fail to reject Ho. The data does not suggest that the difference in average tension bond strengths…

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