A recent survey reported that small businesses spend 29 hours a week marketing their business. A local chamber of commerce claims that small businesses in their areaare not growing because these businesses are spending less than 29 hours a week on marketing. The chamber conducts a survey of 98 small businesses within their stateand finds that the average amount of time spent on marketing is 27.6 hours a week. Assuming that the population standard deviation is 8.1 hours, is there sufficientevidence to support the chamber of commerce's claim at the 0.01 level of significance?Step 3 of 3: Draw a conclusion and interpret the decision.

The null hypothesis (H0) is that the mean time spent on marketing by small businesses in the area is…

Answered: A recent survey reported that small…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Salvatore, as the director of a regional bank, is concerned about the wait times of customers at the four branches. He randomly selects 48 patrons at each branch and records the waiting time for each patron. The results of the samples are shown below. The Alvrine branch has a mean waiting time of 13.49 minutes with a standard deviation of 1.97 minutes.The Durham branch has a mean waiting time of 12.61 minutes with a standard deviation of 2.89 minutes.The Hanover branch has a mean waiting time of 11.06 minutes with a standard deviation of 2.46 minutes.The Mascomonet branch has a mean waiting time of 12.89 minutes with a standard deviation of 3.12 minutes.
Assume a media agency reports that it takes television streaming service subscribers in the U.S. an average of 6.14 days to watch the entire first season of a television series, with a standard deviation of 4.03 days. Scarlett is an analyst for an online television and movie streaming service company that targets to the 18-50 age bracket. She wants to determine if her company's customers exhibit shorter viewing rates for their series offerings. Scarlett plans to conduct a one-sample z-test, with significance level of a = 0.05, to test the null hypothesis, Ho: u = 6.14 days, against the alternative hypothesis, Hj: µ < 6.14 days. The variable u is the mean amount of time, in days, that it takes for customers to watch the first season of a television series. Scarlett selects a simple random sample of 825 customers who watched the first season of a television series from the company database of over 25,000 customers that qualified. She compiles the summary statistics shown in the table.…
a small company is looking to see if they have reached their goal of $30.20, in saving per family. To see if goal was met their goal they randomly surveyed 50 of their 1000 customers, found that they saved average of $32.12 with a standard deviation of $4.83. Have they attained their saving goal.
The America Automobile Association reported that the mean price of a gallon of regular grade gasoline in the United States in October 2020 was $2.82. An economist is interested in determining whether the mean price of regular grade gasoline is cheaper (less than) in New York State. To test this, the economist sample 50 gas stations in NY and find the mean price of regular grade gasoline to be $2.77. Assume the standard deviation for the price of regular grade gasoline is $0.15. Use the critical value method to perform a hypothesis test at the 0.05 level of significance. a. Define the parameter we are testing and setup a hypothesis test to see if the mean price of gas is cheaper in NY compared to the national mean: b. Calculate the test statistics for this hypothesis test. c.What is the critical value for this hypothesis test?
An article by Erin El Issa titled "2015 American household credit card debt study" (www.nerdwallet.com) indicated that for households that had credit card debt, the average debt in 2015 was $15,355. Assume that credit card debt per household has a normal distribution with a standard deviation of $3,000. (A) Determine the percentage of households that have a credit card debt of more than $15,000. Answer: The percentage is % (use 2 decimal places) (B) One household has a credit card debt that is at the 95th percentile. Determine its credit card debt. Answer: The credit card debit is $ Espacio en Blanco 1: Espacio en Blanco 2: Ku
A report about how American college students manage their finances includes data from a survey of college students. Each person in a representative sample of 793 college students was asked if they had one or more credit cards and if so, whether they paid their balance in full each month. There were 500 who paid in full each month. For this sample of 500 students, the sample mean credit card balance was reported to be $825. The sample standard deviation of the credit card balances for these 500 students was not reported, but for purposes of this exercise, suppose that it was $205. Is there convincing evidence that college students who pay their credit card balance in full each month have a mean balance that is lower than $907, the value reported for all college students with credit cards? Carry out a hypothesis test using a significance level of 0.01. State the appropriate null and alternative hypotheses. H0: ? = 907 Ha: ? < 907 H0: ? = 907 Ha: ? > 907 H0: ? < 907…
The providence health maintenance organization wants to establish a criterion for recommending dietary changes if cholesterol levels are in the top 3%. What is the cutoff level for men aged 18 to 24 and the mean is 178.1 and the standard deviation is 40.7
Assume a media agency reports that it takes television streaming service subscribers in the U.S. an average of 6.60 days to watch the entire first season of a television series, with a standard deviation of 4.21 days. Scarlett is an analyst for an online television and movie streaming service company that targets to the 18-50 age bracket. She wants to determine if her company's customers exhibit shorter viewing rates for their series offerings. Scarlett plans to conduct a one-sample ?-z-test, with significance level of ?=0.05α=0.05, to test the null hypothesis, ?0:?=6.60 daysH0:μ=6.60 days, against the alternative hypothesis, ?1:?<6.60 days.H1:μ<6.60 days. The variable ?μ is the mean amount of time, in days, that it takes for customers to watch the first season of a television series. Scarlett selects a simple random sample of 740 customers who watched the first season of a television series from the company database of over 25,000 customers that qualified. She compiles the…
According to the Bureau of Labor Statistics, the mean salary for registered nurses in Kentucky was $57,688. The distribution of salaries is assumed to be normally distributed with a standard deviation of $5,879. Someone would like to determine if registered nurses in Ohio have a greater average pay. To investigate this claim, a sample of 192 registered nurses is selected from the Ohio Board of Nursing, and each is asked their annual salary. The mean salary for this sample of 192 nurses is found to be $58,016.005. 1. Completely describe the sampling distribution of the sample mean salary when samples of size 192 are selected. 2. What conjecture has been made? 3. Using the distribution described in part a, what is the probability of observing a sample mean of 58,016.005 or more? 4. Based on the probability found, what conclusion can be reached?

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