Assume a media agency reports that it takes television streaming service subscribers in the U.S. an average of 6.60 days to watch the entire first season of a television series, with a standard deviation of 4.21 days. Scarlett is an analyst for an online television and movie streaming service company that targets to the 18-50 age bracket. She wants to determine if her company's customers exhibit shorter viewing rates for their series offerings. Scarlett plans to conduct a one-sample ?-z-test, with significance level of ?=0.05α=0.05, to test the null hypothesis, ?0:?=6.60 daysH0:μ=6.60 days, against the alternative hypothesis, ?1:?<6.60 days.H1:μ<6.60 days. The variable ?μ is the mean amount of time, in days, that it takes for customers to watch the first season of a television series. Scarlett selects a simple random sample of 740 customers who watched the first season of a television series from the company database of over 25,000 customers that qualified. She compiles the summary statistics shown in the table. Sample size Sample mean Standard error ? x¯ SE 740 6.32 0.1548   Solve for P - Value

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Assume a media agency reports that it takes television streaming service subscribers in the U.S. an average of 6.60 days to watch the entire first season of a television series, with a standard deviation of 4.21 days. Scarlett is an analyst for an online television and movie streaming service company that targets to the 18-50 age bracket. She wants to determine if her company's customers exhibit shorter viewing rates for their series offerings. Scarlett plans to conduct a one-sample ?-z-test, with significance level of ?=0.05α=0.05, to test the null hypothesis, ?0:?=6.60 daysH0:μ=6.60 days, against the alternative hypothesis, ?1:?<6.60 days.H1:μ<6.60 days. The variable ?μ is the mean amount of time, in days, that it takes for customers to watch the first season of a television series.

Scarlett selects a simple random sample of 740 customers who watched the first season of a television series from the company database of over 25,000 customers that qualified. She compiles the summary statistics shown in the table.

Sample
size
Sample
mean
Standard
error
? SE
740 6.32 0.1548

 

Solve for

P - Value =

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