A rate is equal to 0.0200 M/s. If [A] = 0.100 M and rate = K[A]⁰[B]², what is the new rate if the concentration of [A] is increased to 0.200 M? A. 0.0200 M/s X B. 0.0400 M/S C. 0.0600 M/s D. 0.0800 M/s E. 0.100 M/s
A rate is equal to 0.0200 M/s. If [A] = 0.100 M and rate = K[A]⁰[B]², what is the new rate if the concentration of [A] is increased to 0.200 M? A. 0.0200 M/s X B. 0.0400 M/S C. 0.0600 M/s D. 0.0800 M/s E. 0.100 M/s
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A rate is equal to 0.0200 M/s. If [A] = 0.100 M and rate = k[A]0[B]2, what is the new rate if the concentration of [A] is increased to 0.200 M?
It says the answer was 0.0200 but im not sure, could you check and give me a step by step solution?
![A rate is equal to 0.0200 M/s. If [A] = 0.100 M and rate = K[A]0[B]², what is the new rate if the concentration of [A] is increased to 0.200 M?
A. 0.0200 M/s
X
B. 0.0400 M/S
OC. 0.0600 M/s
D. 0.0800 M/s
E. 0.100 M/s
Answer Key: A](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffade0bae-4c2d-48bb-abcb-ea0806dfa137%2F1cd55ecd-6737-4109-900c-ab349be318fc%2Fd5xdw3e_processed.png&w=3840&q=75)
Transcribed Image Text:A rate is equal to 0.0200 M/s. If [A] = 0.100 M and rate = K[A]0[B]², what is the new rate if the concentration of [A] is increased to 0.200 M?
A. 0.0200 M/s
X
B. 0.0400 M/S
OC. 0.0600 M/s
D. 0.0800 M/s
E. 0.100 M/s
Answer Key: A
Expert Solution
Step 1
Given, the rate law:
Rate = k[A]0[B]2
The rate of the reaction is 0.0200 M/s if [A] = 0.100 M.
We have to find the rate of the reaction when the concentration of [A] is increased to 0.200 M.
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