How many liters of 0.305 M K.PO. solution are necessary to completely react with 187 mL of 0.0184 M NICI2 according to the balanced chemical reaction: 2 K.РO(аq) + NiCl:(aq) → Nis(PO:):(s) + KC((aq) STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 0.0113 1 6.022 x 1023 0.305 187 2 1000 0.001 3 0.00376 0.00752 0.0184 7.52 mL KPO. M KPO. M NICl2 g KPO. L KPO4 mol KPO. mol NiCla mL NiCla

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Please use dimensional analysis
How many liters of 0.305 M K:PO. solution are necessary to completely react with
187
mL of 0.0184 M NICI according to the balanced chemical reaction:
KPO:(aq) +
3
NiCl:(aq) →
Nis(PO:):(s) +
KCI(aq)
STARTING AMOUNT
ADD FACTOR
ANSWER
RESET
*( )
0.0113
1
6.022 x 1023
0.305
187
2
1000
0.001
3
0.00376
0.00752
0.0184
7.52
mL KSPO4
M KPO4
M NICI2
g KPO.
L KPO4
mol KPO4
mol NiCla
mL NiCa
Transcribed Image Text:How many liters of 0.305 M K:PO. solution are necessary to completely react with 187 mL of 0.0184 M NICI according to the balanced chemical reaction: KPO:(aq) + 3 NiCl:(aq) → Nis(PO:):(s) + KCI(aq) STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 0.0113 1 6.022 x 1023 0.305 187 2 1000 0.001 3 0.00376 0.00752 0.0184 7.52 mL KSPO4 M KPO4 M NICI2 g KPO. L KPO4 mol KPO4 mol NiCla mL NiCa
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