How many liters of a 0.209 M KI solution is needed to completely react with 2.43g of Cu(NO:)2 according to the balanced chemical reaction:2 Cu(NO:):(aq) +4KI(aq) - 2 Cul(aq) + I:(s) +4KNO:(aq)STARTING AMOUNTADD FACTORANSWERRESET*( )46.022 x 10230.031016610.2090.1242.43187.570.06200.00542g Cu(NO.)2g KImL KIM KImL Cu(NO:)2mol KIL KImol Cu(NO:)L Cu(NO:)

Given data,Molarity of KI=0.209MMass of Cu(NO3)2=2.43gMolar mass of Cu(NO3)2=187.56g/molMoles of Cu(NO3)2=Mass of Cu(NO3)2Molar mass of Cu(NO3)2 =2.43g187.56g/mol=0.01295moles2 Cu(NO3)2+4KI→2CuI+I2+KNO3according to the balanced equation,2 moles of Cu(NO3)2=4 moles of KI1 mol of Cu(NO3)2=2 moles of KI0.01295moles of Cu(NO3)2=2×0.01295 moles of KI=0.0259 moles of KIVolume of KI needed=Moles of KIMolarity of KI=0.0259mol0.209mol/L=0.124L

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How many iters of a 0.209 M KI solution is needed to completely react with 2.43 g of Cu(NO.) according to the balanced chemical reaction: 2 Cu(NO:):(aq) + 4 KI(aq) - 2 Cul(aq) + l:(S) + 4 KNO:(aq)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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