If 121.6g of NaNO3 is completely dissolved into a solution consisting of volume of 1.25L what is the Ksp of the reaction: [NaNO3= 84.99g/mol]  NaNO3(aq)---> Na^+1(aq) + NO3^-1(aq) A. Ksp= 1.14 B. Ksp= 2.86 C. Ksp= 1.31 D. Ksp= 2.04

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