A random sample of 328 medical doctors showed that 160 had a solo practice. (a) Let p represent the proportion of all medical doctors who have a solo practice. Find a point estimate for p. (Use 3 decimal places.) (b) Find a 99% confidence interval for p. (Use 3 decimal places.) lower limit   upper limit    What is the margin of error based on a 99% confidence interval? (Use 3 decimal places.)

Q: If n = 100 and p (p-hat) = 0.9, construct a 95% confidence %3D interval. Give your answers to three…

A: Givensample size(n)=100p^=0.9α=1-0.95=0.05α2=0.025zc=zα2=z0.025=1.96   (from z table)

Q: 7. (Sec. 7.2) In a survey of 2004 American adults, 501 of them said that they believed in astrology…

A: Introduction:The 100 (1 – α) % confidence interval for the population proportion, π is: (p – (zα/2­)…

Q: 5. In a survey, 8236 out of 9858 doctors recommend aspirin for for their patients with headaches.…

A: Given,n=9858x=8236sample proportion(p^)=xnsample…

Q: or each combination of sample size and sample proportion, find the approximate margin of error for…

A: We find Margin of Error (M.E)  for 95% C.I. (d) (e)

Q: If n = 600 and p (p-hat) = 0.7, construct a 95% confidence interval. Give your answers to three…

A: It is given that, n = 600 and p (p-hat) = 0.7. we have to find the 95% confidence interval for true…

Q: Suppose we wanted to estimate the average amount of sleep (in hours) a college student gets a night.…

A: Confidence interval : Confidence interval is a range of values it contains the true population…

Q: Construct a 95% confidence interval for the proportion of adults from the East who say traffic…

A: n = 400 p = 0.34

Q: And automotive manufacturer wants to know the proportion of new car buyers who prefer foreign over…

A: Solution

Q: Let's say you survey a random sample of people. You find that 53% prefer apples over oranges. You…

A: given data  p^ = 0.5390% ci for p is : (0.448,0.612)based on this ci we have to find the given…

Q: A  95% confidence interval for the  proportion of voters who say "they want change" is computed and…

A: For the population proportion, the confidence interval can be computed using the formulae: C.I=p⏞±E…

Q: The confidence interval at the 95% level of confidence for the true population proportion was…

A: The 95% confidence interval is CI95=(0.665,0.835). We know, that as the level of confidence…

Q: A random sample of 5001 adults in a country includes 755 who do not use the Internet. Construct a…

A:

Q: Suppose that the a college wants to have an idea of the average SAT score of the incoming freshman…

A: The confidence level is 0.90, the standard deviation is 310 and margin of error E is 50.

Q: Out of all the students that attend Yale University, 1,982 were selected to participate in a school…

A:

Q: A researcher wanted to check whether the percentage of Canadian adults with obesity has decreased in…

A: Number of Canadian adults in 2005= 75 Number of Canadian adults in 2009 = 120   significance level =…

Q: A poll conducted randomly in 2014 found that 52% of U.S. adult Twitter users get at least some news…

A: Proportion is 0.52. The standard error 0.024 The absolute value of Zα/2 is 2.5758 using the Excel…

Q: In a random sample of 500 Americans, 50% indicated that they have a cat for a pet. Estimate with 95%…

A: Given information

Q: An environmentalist wants to find out the fraction of oil tankers that have spills each month.…

A:

Q: Free of CVD       Prevalent CVD    Total Men          1548                 244                 1792…

A: Given The tota number of men with CVD =244The tota number of women with CVD =135The tota number of…

Q: In a survey of 2268 adults, 720 say they believe in UFOs. Construct a 90% confidence interval for…

A: Suppose p is the true population proportion adults who believe in UFOs.

Q: A study found a confidence interval on the proportion of children that are hearing impaired was 0.04…

A: Given confidence interval is 0.04 to 0.16 i.e., p-E=0.04 -->1 p+E=0.16 -->2

Q: A researcher wanted to compare the percentages of men and women who play the lottery.  They randomly…

A:

Q: was the percentage of adults who used social media five years ago. Of the 2703 people who responded…

A: (a) The sample proportion is: p= x/n=1758/2703 =0.65 The value of z at 92% confidence level is 1/75,…

Q: Do college students prefer printed textbooks to electronic textbooks? You work for a textbook…

A: The confidence interval gives a range of values in which the population parameter lies with certain…

Q: The FBI wants to determine the effectiveness of their 10 Most Wanted list. To do so, they need to…

A:

Q: Assume that the following samples are independent. In a random sample of 400 women, 47% favored…

A: Obtain the 98% confidence interval for the difference between the population proportions.   The 98%…

Q: If N=480 and p̂ (p-hat) =0.88, find the margin of error at a 95% confidence level.

A: From the provided information, Sample size (n) = 480 p̂ (p-hat) =0.88 Confidence level = 95%

Q: Which one of the following statements about confidence intervals is false?   Given the same sample…

A: In this case, we need to identify the false statement for confidence interval.

Q: Do college students prefer printed textbooks to electronic textbooks? You work for a textbook…

A: Given:   Number  Proportion Prefer 28 0.7 Does not prefer 12 0.3

Q: What is the effect on the size of the confidence interval if a T score is used instead of a Z score?…

A: The formula for calculating confidence interval using Z score is as follow:

Q: Suppose we wish to construct a 95% confidence interval for the population proportion of fans in…

A: Given that, Total fans = 200 130 answered yes 95% confidence level

Q: You recently sent out a survey to determine if the percentage of adults who use social media has…

A: Given  The percentage of adults who use social media 5 years ago  =   62% Out of 2751, 1740 using…

Q: A 90% confidence interval for the difference between the proportion of college students who use…

A:

Q: According to a poll, 86% of California adults (434 out of 506 surveyed) feel that education is one…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.