Nielsen ratings are based on televisions in 7000 households. Nielsen estimates that 19,000 people live in these households. Suppose Nielsen reports that American Idol had 75% of the TV audience. Interpret this result with a 95% confidence interval, based on a sample size of 19,000 people. Margin of error = 0.7 % (Round to one decimal place as needed.) Confidence interval is from % to %.

Q: Ninety-four percent of students said that cash is their top choice for a graduation gift. If 75…

A: It is given that sample size (n) is 75and the sample proportion value is 0.94.

Q: Of 500 random people surveyed, 72 were smokers.  Find the 95% confidence interval. SE=0.0157

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A: Given Mean=50 Standard deviations=9.9 n=81

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Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

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A: Given data, n=152 x=101 p=x/n =0.664 The 95% CI is Zc=1.96

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A: Given data n=200 p=23% confidence level=99%

Q: Suppose you calculate a 99% confidence interval to be: 13.05 to 20.75. Determine the margin of error

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Q: In statistics, what is a Confidence Interval and how confidence intervals are used in research

A: We have define the confidence interval . Also we have find the its use in the research

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Q: In a study of 120 randomly selected families, 50 said they streamed their television content. Find…

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Q: A random sample of 900 car owners in a particular city found 252 car owners who received a speeding…

A: Given,n=900x=252p^=xnp^=252900=0.281-p^=1-0.28=0.72α=1-0.95=0.05α2=0.025Z0.025 =1.96   (from…

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A: Given that  Sample size n =30 90 % confidence interval is (40 , 55)

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Q: In a survey of 2255 adults, 741 say they believe in UFOS. Construct a 95% confidence interval for…

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Q: one with a 95% confidence level and the other with a 99.7% confidence level. Which interval is…

A: Confidence interval is probability, which refers that population parameter will fall within set of…

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A: As per honor code, we will only answer first question: 1)  p=0.52 n=84, p^=0.42 Use the formula of…

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A: Given , n = 1008 x = 598

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A: The formula of the margin of error when the limits given are,

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Q: Out of 300 people sampled, 24 had kids. Based on this, construct a 95% confidence interval for the…

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A: Using Excel formula “=NORM.S.INV(1-(0.01/2))”, the critical value for 99% confidence level is…

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A: Obtain the 99% confidence interval for the true population proportion. The 99% confidence interval…

Q: A research institute poll asked respondents if they felt vulnerable to identify a theft. In the poll…

A: Given,n=1000x=501p^=xnp^=5011000=0.5011-p^=1-0.501=0.499α=1-0.99=0.01α2=0.005Z0.005=2.58    (from…

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A: Sample size is, Population mean is Confidence Level is The objective is to test the claim that the…

Q: 9. A survey of 280 homeless persons showed that 63 were veterans. Construct a 90% confidence…

A: In a survey of 280 homeless persons showed that 63 were veterans.

Q: In a survey of 2291 adults, 743 say they believe in UFOs. Construct a 99% confidence interval for…

A: sample size(n)=2291No. of adults say they believe in UFOs(x)=743

Q: In a survey of 2286 ​adults, 745 say they believe in UFOs.   Construct a 90% confidence interval for…

A: Proportion is almost similar to the concept of probability. Proportion is a fraction of population…

Q: You're considering going to graduate school, and you would like to know how many people would…

A: Given: X= 6, N=28. Therefore, P=XN=628=0.214

Q: ou're considering going to graduate school, and you would like to know how many people would…

A: Given data, n=30 x=7 p=x/n =7/30 =0.23 z-value at 96% confidence is Zc=2.05

Q: In a survey of 2480 golfers, 372 said they were left-handed. Construct a 92% confidence interval for…

A: GIVEN DATA : Total number of golfers are 2480, Number of left handed golfer are 372        TO FIND :…

Q: Find the margin of error for the​ 99% confidence interval used to estimate the population…

A: p^ : Sample Proportion 35% of the patients showed improvement. So, probability that a patient shows…

Q: Find the margin of error for the​ 99% confidence interval used to estimate the population…

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A: The CI for the population proportion, p^±Zp^ (1-p^)nwhere, p^=sample proportion…

Q: Out of 500 people sampled, 145 received flu vaccinations this year. Based on this, construct a 90%…

A: We have given that  Sample size n=500 , favorable cases x=145 90% confidence interval  Sample…

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