The decision can be made to:- ○ reject $ H_0 $- ○ do not reject $ H_0 $The final conclusion is that:- ○ There is enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida.- ○ There is not enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida.- ○ There is enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida.- ○ There is not enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida. A random sample of 21 chemists from Washington state shows an average salary of $43,206 with a standard deviation of $916. A random sample of 20 chemists from Florida state shows an average salary of $43,138 with a standard deviation of $716. A chemist that has worked in both states believes that chemists in Washington make a different amount than chemists in Florida. At α=0.10 is this chemist correct? Let Washington be sample 1 and Florida be sample 2.The correct hypotheses are:- $ H_0: \mu_1 \leq \mu_2 $- $ H_A: \mu_1 > \mu_2 $ (claim)- $ H_0: \mu_1 \geq \mu_2 $- $ H_A: \mu_1 < \mu_2 $ (claim)- $ H_0: \mu_1 = \mu_2 $- $ H_A: \mu_1 \neq \mu_2 $ (claim)Since the level of significance is 0.10, the critical value is 1.686 and -1.686.The test statistic is: [__________] (round to 3 places)The p-value is: [__________] (round to 3 places)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Given Data :

For Sample 1

x̄1 = 43206.0

s1 = 916.0

n1 = 21

For Sample 2

x̄2 = 43138.0

s2 = 716.0

n2 = 20

Significance level, α= 0.1

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