There are frogs and koi in a pond, and the number of frogs and the number of koi in the pond are independent. Let X represent the number of frogs in any given week, and let Y represent the number of koi in any given week. X has a mean of 28 with a standard deviation of 2.7, and Y has a mean of 15 with a standard deviation of 1.6. Which answer choice correctly calculates and interprets the standard deviation of the difference, D = X - Y? = 1.05; this pond can expect the difference of frogs and koi to vary by approximately 1.05 from the mean. = 1.1; this pond can expect the difference of frogs and koi to vary by approximately 1.1 from the mean. = 3.1; this pond can expect the difference of frogs and koi to vary by approximately 3.1 from the mean. = 13; this pond can expect the difference of frogs and koi to vary by approximately 1.05 from the mean.
There are frogs and koi in a pond, and the number of frogs and the number of koi in the pond are independent. Let X represent the number of frogs in any given week, and let Y represent the number of koi in any given week. X has a mean of 28 with a standard deviation of 2.7, and Y has a mean of 15 with a standard deviation of 1.6. Which answer choice correctly calculates and interprets the standard deviation of the difference, D = X - Y? = 1.05; this pond can expect the difference of frogs and koi to vary by approximately 1.05 from the mean. = 1.1; this pond can expect the difference of frogs and koi to vary by approximately 1.1 from the mean. = 3.1; this pond can expect the difference of frogs and koi to vary by approximately 3.1 from the mean. = 13; this pond can expect the difference of frogs and koi to vary by approximately 1.05 from the mean.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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There are frogs and koi in a pond, and the number of frogs and the number of koi in the pond are independent. Let X represent the number of frogs in any given week, and let Y represent the number of koi in any given week. X has a mean of 28 with a standard deviation of 2.7, and Y has a mean of 15 with a standard deviation of 1.6. Which answer choice correctly calculates and interprets the standard deviation of the difference, D = X - Y?
= 1.05; this pond can expect the difference of frogs and koi to vary by approximately 1.05 from the mean.
= 1.1; this pond can expect the difference of frogs and koi to vary by approximately 1.1 from the mean.
= 3.1; this pond can expect the difference of frogs and koi to vary by approximately 3.1 from the mean.
= 13; this pond can expect the difference of frogs and koi to vary by approximately 1.05 from the mean.
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