Alex's times for running a mile are Normally distributed with a mean time of 5.28 minutes and a standarddeviation of 0.38 seconds. Chris's times for running a mile are Normally distributed with a mean time of 5.45seconds and a standard deviation of 0.2 seconds. Ten of Alex's times and 15 of Chris's times are randomlyselected. Let i, -i, represent the difference in the mean times for Alex and Chris. Which of the followingrepresents the standard deviation of the sampling distribution for i,-?0.090.130.170.18

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Answered: Alex's times for running a mile are…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The mean time taken by all participants to run a road race was found to be 155 minutes with a standard deviation of 15 minutes. Using Chebyshev's theorem, find the percentage of runners who ran this road race in 125 to 185 minutes.Round your answer to the nearest integer.Enter your answer in accordance to the question statement %
Internet Service Providers The amount that households pay service providers for access to the Internet varies quite a bit, but the mean monthly fee is $50 and the standard deviation is $20. The distribution is not Normal: many households pay a low rate as part of a bundle with phone or television service, but some pay much more for Internet only or for faster connections. A sample survey asks an SRS of 50 households with Internet access how much they pay. Let x be the mean amount paid. 1. Explain why you can't determine the probability that the amount a randomly selected household pays for access to the Internet exceeds $55. 2. What are the mean and standard deviation of the sampling distribution of x ? 3. What is the shape of the sampling distribution of x ? Justify your answer. 4. Find the probability that the average fee paid by the sample of households exceeds $55.
A standardized exam's scores are normally distributed. In a recent year, the mean test score was 1529 and the standard deviation was 320. The test scores of four students selected at random are 1970, 1280, 2220, and 1410. Find the z-scores that correspond to each value and determine whether any of the values are unusual. The z-score for 1970 is. (Round to two decimal places as needed.) The z-score for 1280 is (Round to two decimal places as needed.) The z-score for 2220 is (Round to two decimal places as needed.) The z-score for 1410 is (Round to two decimal places as needed.) Which values, if any, are unusual? Select the correct choice below and, if necessary, fill in the answer box within your choice. A. The unusual value(s) is/are (Use a comma to separate answers as needed.) B. None of the values are unusual.
Assume that adults have IQ scores that are normally distributed with a mean of u = 100 and a standard deviation o = 15. Find the probability that a randomly selected adult has an IQ between 84 and 116. Click to view page 1 of the table. Click to view page 2 of the table. The probability that a randomly selected adult has an IQ between 84 and 116 is (Type an integer or decimal rounded to four decimal places as needed.)
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P80, the 80-percentile. This is the temperature reading separating the bottom 80% from the top 20%.P80 = °C
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P33, the 33-percentile. This is the temperature reading separating the bottom 33% from the top 67%. P33 = %3D
Assume that thermometer readings are normally distributed with a mean of 0degrees°C and a standard deviation of 1.00degrees°C. A thermometer is randomly selected and tested. (The given values are in Celsius degrees.) Between -1.47and 1.76
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P61, the 61-percentile. This is the temperature reading separating the bottom 61% from the top 39%.P61 =
Assume that adults have IQ scores that are normally distributed with a mean of u= 100 and a standard deviation g= 15. Find the probability that a randomly selected adult has an IQ less than 118. Click to view page 1 of the table. Click to view page 2 of the table. The probability that a randomly selected adult has an IQ less than 118 is (Type an integer or decimal rounded to four decimal places as needed.)
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P30, the 30-percentile. This is the temperature reading separating the bottom 30% from the top 70%.P30 = °C(Round answer to three decimal places)
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P., the 58- percentile. This is the temperature reading separating the bottom 58% from the top 42%. P = °C Question Help: D Post to forum Submit Question Type here to search 耳

Use z scores to compare the given values. The tallest living man at one time had a height of 238 cm. The shortest living man at that time had a height of 142.4 cm. Heights of men at that time had a mean of 175.45 cm and a standard deviation of 5.59 cm. Which of these two men had the height that was more extreme? ... Since the z score for the tallest man is z = 0 and the z score for the shortest man is z = the man had the height that was Im- more extreme. (Round to two decimal places.) shortest tallest

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