.SOlve for all the parts in the question correctly. B)According to researchers, the mean length of imprisonment for motor vehicle-theft offenders in a nation is 15.7 months. One hundred randomly selected motor-vehicle-theft offenders in a city in the nation had a mean length of imprisonment of 16.7 months. It is assumed that the population standard deviation of the lengths of imprisonment for motor-vehicle-theft offenders in the city is 6.0 months. At the 5% significance level, the data do not provide sufficient evidence to conclude that the mean length of imprisonment for motor-vehicle theft offenders in the city differs from the national mean. The confidence interval is(enter your response here) B2)= Since the population mean( is not, is ?) in the confidence interval, this( ? ) sufficient evidence to conclude that the mean length of imprisonment for motor-vehicle-theft offenders in the city differs from the national mean. This (is not, is) the same conclusion reached by the hypothesis test. For a two-tailed hypothesis test at the significance level a, the null hypothesis Ho: µ= Ho will be rejected in favor of the alternative hypothesis Ha: µ# Ho if and only if Ho lies outside the(1 - a)-level confidence interval for u. Illustrate the preceding relationship by obtaining the appropriate one-mean z-interval for the situations described in parts (a) and (b) below.Click here to view page 1 of the table of areas under the standard normal curve. Click here to view page 2 of the table of areas under the standard normal curve......a. The average lactation (nursing) period of all earless seals is 23 days. For a sample of 14 female grey seals, the average lactation period is 21.8 days. It is assumed that the populationstandard deviation is 3.0 days. At the 5% significance level, the data do not provide sufficient evidence to conclude that the mean lactation period of grey seals differs from 23 days.The confidence interval is ( , ).(Round to two decimal places as needed.) Since the population meanin the confidence interval, thissufficient evidence to conclude that the average lactation period of grey seals differs from 23 days. Thisthe same conclusion reached by the hypothesis test.

a) It is given that the sample mean is 21.8 and the population standard deviation is 3.0.

Answered: .SOlve for all the parts in the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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.SOlve for all the parts in the question correctly.

According to researchers, the mean length of imprisonment for motor vehicle-theft offenders in a nation is 15.7 months. One hundred randomly selected motor-vehicle-theft offenders in a city in the nation had a mean length of imprisonment of 16.7 months. It is assumed that the population standard deviation of the lengths of imprisonment for motor-vehicle-theft offenders in the city is 6.0 months. At the 5% significance level, the data do not provide sufficient evidence to conclude that the mean length of imprisonment for motor-vehicle theft offenders in the city differs from the national mean.

The confidence interval is

(enter your response here)

B2)= Since the population mean( is not, is ?) in the confidence interval, this

( ? ) sufficient evidence to conclude that the mean length of imprisonment for motor-vehicle-theft offenders in the city differs from the national mean. This (is not, is) the same conclusion reached by the hypothesis test.

For a two-tailed hypothesis test at the significance level a, the null hypothesis Ho: µ= Ho will be rejected in favor of the alternative hypothesis Ha: µ# Ho if and only if Ho lies outside the
(1 - a)-level confidence interval for u. Illustrate the preceding relationship by obtaining the appropriate one-mean z-interval for the situations described in parts (a) and (b) below.
Click here to view page 1 of the table of areas under the standard normal curve. Click here to view page 2 of the table of areas under the standard normal curve.
.....
a. The average lactation (nursing) period of all earless seals is 23 days. For a sample of 14 female grey seals, the average lactation period is 21.8 days. It is assumed that the population
standard deviation is 3.0 days. At the 5% significance level, the data do not provide sufficient evidence to conclude that the mean lactation period of grey seals differs from 23 days.
The confidence interval is ( , ).
(Round to two decimal places as needed.)

Since the population mean
in the confidence interval, this
sufficient evidence to conclude that the average lactation period of grey seals differs from 23 days. This
the same conclusion reached by the hypothesis test.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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