A railroad car of mass 3.50 x 104 kg moving at 2:70 m/s collides and couples with two coupled railroad cars, each of the same mass as the single car and moving in the same direction at 1.20 m/s. (a) What is the speed of the three coupled cars after the collision? 3 m/s (b) How much kinetic energy is lost in the collision?
A railroad car of mass 3.50 x 104 kg moving at 2:70 m/s collides and couples with two coupled railroad cars, each of the same mass as the single car and moving in the same direction at 1.20 m/s. (a) What is the speed of the three coupled cars after the collision? 3 m/s (b) How much kinetic energy is lost in the collision?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:### Problem Statement
A railroad car of mass \(3.50 \times 10^4 \, \text{kg}\) moving at \(2.70 \, \text{m/s}\) collides and couples with two coupled railroad cars, each of the same mass as the single car and moving in the same direction at \(1.20 \, \text{m/s}\).
#### Questions:
(a) What is the speed of the three coupled cars after the collision?
- Answer: \(3 \, \text{m/s}\)
(b) How much kinetic energy is lost in the collision?
- Answer: \( \, \text{J}\)
### Explanation
This problem involves a collision and coupling of railroad cars, a classic physics problem that explores the conservation of momentum and kinetic energy in inelastic collisions. The equation for the conservation of momentum can be used to find the final speed after the collision. Energy analysis can determine how much kinetic energy is lost.
### Additional Resources
For detailed explanations and example problems on momentum and energy conservation, visit our tutorials section. If you need extra help, click on "Read It" for further assistance.
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