Answered: On a horizontal frictionless surface, a…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

On a horizontal frictionless surface, a small block with a mass 0.200kg has a collision with a block of mass 0.400kg. Immediately after the collision, the 0.200kg block is moving at 12.0m/s in the direction 30° north of east and the 0.400kg is moving at 12.6m/s in the direction 53.1° south of east. a) what is the total kinetic energy of the two blocks after the collision (in joules) b) what is the the x-component of the total momentum of the two blocks after the collision? c) what is the the y-component of the total momentum of the two blocks after the collision?

Expert Solution

Step 1: Given data

Mass of object 1 is $m subscript 1 equals 0.200 space kg$

Mass of object 2 is $m subscript 2 equals 0.400 space kg$

After collision, velocity of object 1 is $v subscript 1 equals 12 space straight m divided by straight s$ in the direction $30 to the power of degree$ north of east.

After collision, velocity of object 2 is $v subscript 2 equals 12.6 space straight m divided by straight s$ in the direction $53.1 to the power of degree$ south of east.

Note:

$1 space straight N equals 1 space kg times straight m divided by straight s squared$

$1 space straight J equals 1 space straight N times straight m$

Find:

(a) Total kinetic energy of the objects after collision.

(b) The x-component of the total momentum of objects after collision.

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