A pitcher claims he can throw a 0.148-kg baseball with as much momentumas a 2.48-g bullet moving with a speed of 1.50 x 103 m/s.(a) What must the baseball's speed be if the pitcher's claim is valid?m/s(b) Which has greater kinetic energy, the ball or the bullet?The ball has greater kinetic energy.The bullet has greater kinetic energy.O Both have the same kinetic energy.

Answered: che е | bartleby

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

A pitcher claims he can throw a 0.148-kg baseball with as much momentum
as a 2.48-g bullet moving with a speed of 1.50 x 103 m/s.
(a) What must the baseball's speed be if the pitcher's claim is valid?
m/s
(b) Which has greater kinetic energy, the ball or the bullet?
The ball has greater kinetic energy.
The bullet has greater kinetic energy.
O Both have the same kinetic energy.

Expert Solution

Step 1

Momentum of an object with a mass $m$ is given by the product of the mass and velocity $v$ with which it is moving. So let us consider the velocity of baseball as $v$ . Now the mass of bullet is 2.48 $g m$ . It can be converted to SI which is given by,

$2.48 \times 10^{- 3} k g$ . Velocity of bullet is $1.50 \times 10^{3}$ . So we can compare the momentum of both the objects to find out the velocity of the baseball.

$0.148 \times v = 2.48 \times 10^{- 3} (1.50 \times 10^{3})$

$v = \frac{(2.48) (1.50)}{0.148}$

$v = 25.14 m / s$

Thus velocity of baseball must be 25.14m/s.

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