A 38.0 kg soccer player jumps vertically upwards and heads the 0.45 kg ball as it is descending vertically with a speed of 22.0 m/s. If the player was moving upward with a speed of 2.70 m/s just before impact. (d) What will be the speed of the ball immediately after the collision if the ball rebounds vertically upwards and the collision is elastic? (Note that the force of gravity may be ignored during the brief collision time.)
A 38.0 kg soccer player jumps vertically upwards and heads the 0.45 kg ball as it is descending vertically with a speed of 22.0 m/s. If the player was moving upward with a speed of 2.70 m/s just before impact. (d) What will be the speed of the ball immediately after the collision if the ball rebounds vertically upwards and the collision is elastic? (Note that the force of gravity may be ignored during the brief collision time.)
A 38.0 kg soccer player jumps vertically upwards and heads the 0.45 kg ball as it is descending vertically with a speed of 22.0 m/s. If the player was moving upward with a speed of 2.70 m/s just before impact. (e) If the ball is in contact with the players head for 49 ms, what is the average acceleration of the ball? (Note that the force of gravity may be ignored during the brief collision time.)
A 38.0 kg soccer player jumps vertically upwards and heads the 0.45 kg ball as it is descending vertically with a speed of 22.0 m/s. If the player was moving upward with a speed of 2.70 m/s just before impact. (f) If the ball is in contact with the players head for 49 ms, what is the average force on the ball?(Note that the force of gravity may be ignored during the brief collision time.)
Introduction:
Newton's laws of motion best describe the motion of the particle. According to Newton's 2nd law of motion applied force is depend on the change in momentum of the body. In every physical problem momentum is conserved quantity. Momentum is the product of mass and velocity.
Given data:
Mass of the soccer player is,
mp=38 kg
mass of the ball is,
mb= 0.45 kg
Initially before the collision,
Ball is descending vertically with a speed of 22.0 m/s.
vbi= -22 m/s
The player was moving upward with a speed of 2.70 m/s,
vpi= 2.70 m/s
Formula used:
Momentum of the object is,
p=mv
According to cond]servation of linear momentum,
(Initial momentum)= (Final Momentum)
Where,
pi- Initial Momentum
pf- Final Momentum
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