A quality control engineer is in charge of the manufacture of computer disks. Two different processes can be used to manufacture the disks. He suspects that the Kohler method produces a greater proportion of defects than the Russell method. He samples 150 of the Kohler and 200 of the Russell disks and finds that 27 and 18 of them, respectively, are defective. Assume that Kohler is designated as "Group 1" and Russell is designated as "Group 2". Referring to the information above, construct a 99% confidence interval estimate of the difference in proportion between the Kohler and Russell disks that are defective. The upper bound of the interval is (to 2 d. p.)
A quality control engineer is in charge of the manufacture of computer disks. Two different processes can be used to manufacture the disks. He suspects that the Kohler method produces a greater proportion of defects than the Russell method. He samples 150 of the Kohler and 200 of the Russell disks and finds that 27 and 18 of them, respectively, are defective. Assume that Kohler is designated as "Group 1" and Russell is designated as "Group 2". Referring to the information above, construct a 99% confidence interval estimate of the difference in proportion between the Kohler and Russell disks that are defective. The upper bound of the interval is (to 2 d. p.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
![A quality control engineer is in charge of the manufacture of computer
disks. Two different processes can be used to manufacture the disks. He
suspects that the Kohler method produces a greater proportion of defects
than the Russell method. He samples 150 of the Kohler and 200 of the
Russell disks and finds that 27 and 18 of them, respectively, are defective.
Assume that Kohler is designated as "Group 1" and Russell is designated as
"Group 2" . Referring to the information above, construct a 99% confidence
interval estimate of the difference in proportion between the Kohler and
Russell disks that are defective. The upper bound of the interval is (to
2 d. p.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1c0c823a-e3d2-414f-aa4d-018a49ac722f%2F62635296-2cff-4f64-acd0-34f621422b81%2Fpmztzxp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A quality control engineer is in charge of the manufacture of computer
disks. Two different processes can be used to manufacture the disks. He
suspects that the Kohler method produces a greater proportion of defects
than the Russell method. He samples 150 of the Kohler and 200 of the
Russell disks and finds that 27 and 18 of them, respectively, are defective.
Assume that Kohler is designated as "Group 1" and Russell is designated as
"Group 2" . Referring to the information above, construct a 99% confidence
interval estimate of the difference in proportion between the Kohler and
Russell disks that are defective. The upper bound of the interval is (to
2 d. p.)
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