A proton traveling at the speed of light (c = 3.0 x 10 m/s) through a uniform magnetic field of strength 1.49 T, experiences a force of magnitude 3.85 x 10¹¹ N. At what angle -11 does the proton enter the field? O 41° O 53° O 33° 29°
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![A proton traveling at the speed of light (c =
3.0 x 10 m/s) through a uniform magnetic
field of strength 1.49 T, experiences a force
of magnitude 3.85 x 10 N. At what angle
does the proton enter the field?
-11
O 41°
O 53°
O 33°
O 29°](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa6f61744-dd70-4311-84b4-0816ebfea9f9%2Fb22758d7-9c95-4cf1-b9f1-376396804511%2F7bwxm89_processed.jpeg&w=3840&q=75)
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- = A proton moves through a region containing a uniform electric field given by E 48.0 ĵ V/m and a uniform magnetic field B (0.200 î + 0.300 ĵ + 0.400 K) T. Determine the acceleration of the proton when it has a velocity ✓ = 170 î m/s. ↑ m/s² =A cosmic ray electron moves at 7.5 × 106 m/s perpendicular to the Earth's magnetic field at an altitude where the field strength is 1.0 × 10-5 T. What is the radius, in meters, of the circular path the electron follows?A particle with a charge of q = - 1.24 × 10-8 ℃ is moving with instantaneous velocity V = 1.42 x 104 m/si +3.85 x 104 m/sĵ. What is the force exerted on this particle by a magnetic field: a) B = 11.4 TÎ and b) B = 11.4Tk?
- A magnetic field has a magnitude of 0.0018 T, and an electric field has a magnitude of 3.9 × 10³ N/C. Both fields point in the same direction. A positive 2.3-µC charge moves at a speed of 3.3 × 106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge. Number i Units B V + 9 90° 1>As shown in the figure below, when a charged particle enters a region of magnetic field traveling in a direction perpendicular to the field, it will travel in a circular path. If the magnitude of the magnetic field is 0.170 T, the speed of the particle is 12.0 x 10° m/s, the radius of the trajectory of the path is 105.5 cm, and the charge has a magnitude of 3.20 x 1019 C, determine the following. B (a) sign of the charged particle O positive O negative (b) mass of the particle (use the conversion 1 u = 1.66 x 10-27 kg)An electron in the beam of a TV picture tube is accelerated by a potential difference of 1.94 kV. Then it passes through a region of the transverse magnetic field, where it moves in a circular arc with a radius of 0.178 m. What is the magnitude of the field? Use 9.11×10−31 kg for the mass of an electron and 1.60×10−19 CC for the magnitude of the charge on an electron.
- A proton moves perpendicularly to a mag- netic field that has a magnitude of 3.00 × 10−2 T. The charge on a proton is 1.60×10−19 C. What is the speed of the particle if the magnitude of the magnetic force on it is 1.91× 10−14N? Answer in units of m/s.A proton experiences the greatest force as it travels 2.9 x 106 m/s in a magnetic field when it is moving northward. The force is upward and of magnitude 7.2 x10-13 N. What is the magnitude and direction of the magnetic field?A beryllium-9 ion has a positive charge that is double the charge of a proton, and a mass of 1.50 ✕ 10−26 kg. At a particular instant, it is moving with a speed of 5.10 ✕ 106 m/s through a magnetic field. At this instant, its velocity makes an angle of 62° with the direction of the magnetic field at the ion's location. The magnitude of the field is 0.220 T. (a) What is the magnitude of the magnetic force (in N) on the ion? N (b) What is the magnitude of the ion's acceleration (in m/s2) at this instant? m/s2
- A proton travels with a speed of (5.3x10^4) m/s along the x-axis. A uniform magnetic field of strength (9.200x10^-4) T directed along the y-axis is turned on, and the proton starts travelling in a circle due to the magnetic force. What is the radius of this circle? Give your answer in meters (m) using scientific notation.Two long parallel wires both carry a current of 158 A in the +z direction. One wire passes through the x-axis at x = 0.028 m, and the other passes through the y-axis at y = 0.088 m. What is the magnitude of the magnetic field at the origin? O 0.00107 T O 0.000217 T O 0.00118 T O 0.000592 Ta) At what speed (in m/s) will a proton move in a circular path of the same radius as an electron that travels at 7.45 ✕ 106 m/s perpendicular to the Earth's magnetic field at an altitude where the field strength is 1.25 ✕ 10−5 T? b) What would the radius (in m) of the path be if the proton had the same speed as the electron? c) What would the radius (in m) be if the proton had the same kinetic energy as the electron? d) What would the radius (in m) be if the proton had the same momentum as the electron?