An electron in the beam of a TV picture tube is accelerated by a potential difference of 1.94 kV. Then it passes through a region of the transverse magnetic field, where it moves in a circular arc with a radius of 0.178 m. What is the magnitude of the field? Use 9.11×10−31 kg for the mass of an electron and 1.60×10−19 CC for the magnitude of the charge on an electron.
An electron in the beam of a TV picture tube is accelerated by a potential difference of 1.94 kV. Then it passes through a region of the transverse magnetic field, where it moves in a circular arc with a radius of 0.178 m. What is the magnitude of the field? Use 9.11×10−31 kg for the mass of an electron and 1.60×10−19 CC for the magnitude of the charge on an electron.
Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter28: Magnetic Fields
Section: Chapter Questions
Problem 9P: A proton (charge + e, mass mp), a deuteron (charge + e, mass 2mp), and an alpha particle (charge...
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An electron in the beam of a TV picture tube is accelerated by a potential difference of 1.94 kV. Then it passes through a region of the transverse magnetic field, where it moves in a circular arc with a radius of 0.178 m.
What is the magnitude of the field?
Use 9.11×10−31 kg for the mass of an electron and 1.60×10−19 CC for the magnitude of the charge on an electron.
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