A proton traveling at 19.3° with respect to the direction of a magnetic field of strength 2.70 mT experiences a magnetic force of 5.72 × 10-17 N. Calculate (a) the proton's speed and (b) its kinetic energy in electron-volts. (a) Number i Units (b) Number 835 Units ev
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A: velocity of proton = 0.75 c , northwards magnetic field (B) = 8.3 T , due east
Q: A proton traveling at 28.7° with respect to the direction of a magnetic field of strength 3.23 mT…
A: The answers are below
Q: A proton traveling at 34.2° with respect to the direction of a magnetic field of strength 3.38 mT…
A: Given value--- angle = 34.2 degree. magnetic field = 3.38 mR. magnetic force = 6.40 × 10-17 N. We…
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Q: A proton traveling at 24.6° with respect to the direction of a magnetic field of strength 2.50 mT…
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Q: A proton traveling at 18.6° with respect to the direction of a magnetic field of strength 2.88 mT…
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Q: A proton moves through a magnetic field at 25.7% of the speed of light. At one location, the field…
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A: proton is moving perpendicular which means angle θ =900 Force F =6.0 × 10-21 N Magnetic field B =3.2…
Q: A proton traveling at 33.3° with respect to the direction of a magnetic field of strength 3.14 mT…
A: θ = 33.3oB = 3.14 mT F = 6.73×10-17 N
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A:
Q: A proton traveling at 19.2° with respect to the direction of a magnetic field of strength 3.00 mT…
A: Given data: Angle between velocity and magnetic field (θ) = 19.2° Magnetic field (B) = 3.00 mT =…
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- A proton traveling at 23.9 degrees with respect to the direction of a magnetic field of strength 2.50 mT experiences a magnetic force of 5.52 x 10-17 N. Calculate (a) the proton's speed and (b) its kinetic energy in electron-volts.A proton experiences the greatest force as it travels 2.9 x 106 m/s in a magnetic field when it is moving northward. The force is upward and of magnitude 7.2 x10-13 N. What is the magnitude and direction of the magnetic field?A proton traveling at 24.7° with respect to the direction of a magnetic field of strength 2.33 mT experiences a magnetic force of 6.38 × 10-17 N. Calculate (a) the proton's speed and (b) its kinetic energy in electron-volts.
- A proton traveling at 17.8° with respect to the direction of a magnetic field of strength 3.75 mT experiences a magnetic force of 6.19 x 10-17 N. Calculate (a) the proton's speed and (b) its kinetic energy in electron-volts. (a) Number i (b) Number i Units UnitsA proton enters a magnetic field in such a way that it is traveling perpendicularly to the magnetic field lines. If the proton moves in a circle of radius 125 mm, and feels a force of 5.88 x 10 -16 N, how fast is the proton traveling?Starting from rest, an electron is accelerated through a region between two oppositely charged plates, as shown in Figure 1. The distance between the plates is 10 cm and the magnitude of the potential difference between them is 100 V. Immediately after exiting the region with the uniform electric field, the electron enters a region with a uniform magnetic field of 0.85 T, directed into the page. (a) Calculate the magnitude of the electric force on the electron. (b) Calculate the work done by the electric force on the electron. (c) Determine the electron's speed when it enters the magnetic field. (d) Determine the magnitude and direction of the magnetic force on the electron when it enters the magnetic field. (e) Suppose that the experiment was repeated with the locations of the positive and negative plates switched, and the electron was replaced with a proton, but nothing else was changed. Calculate R,/R., the ratio of the radius of the proton's path in the magnetic field (R,) to that…
- Chapter 28, Problem 001 A proton traveling at 23.8° with respect to the direction of a magnetic field of strength 1.98 mT experiences a magnetic force of 9.59 × 10-¹7 N. Calculate (a) the proton's speed and (b) its kinetic energy in electron- volts. Chapter 28, Problem 009 In the figure, an electron accelerated from rest through potential difference V₁=1.06 kV enters the gap between two parallel plates having separation d = 24.5 mm and potential difference V₂= 99.1 V. The lower plate is at the lower potential. Neglect fringing and assume that the electron's velocity vector is perpendicular to the electric field vector between the plates. In unit-vector notation, what uniform magnetic field allows the electron to travel in a straight line in the gap? [₁}v₂= The figure shows a solid metal object moving through a uniform magnetic field given by B (7.00 x 10-2T) k. The motion creates a potential difference of 1.30 x 103 V across the object, with the (unseen) bottom face negatively charged. What is the speed (m/s) of the object? d₁=5.00 x 102 m, d2= 3.00 x 102 m, d3 = 2.00 × 10² m. A do ds