A probe of mass 100 kg is coasting through a dense gas cloud in deep space, where g = 0. There is drag from the gas cloud and it is modeled by the equation -0.38 v (N). If the probe entered the gas cloud with speed 1,047 m/s, how much time, in s, will it take for the probe's speed to be reduced to 14 percent of its initial velocity? (Please answer to the fourth decimal place)
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A probe of mass 100 kg is coasting through a dense gas cloud in deep space, where g = 0. There is drag from the gas cloud and it is modeled by the equation -0.38 v (N). If the probe entered the gas cloud with speed 1,047 m/s, how much time, in s, will it take for the probe's speed to be reduced to 14 percent of its initial velocity? (Please answer to the fourth decimal place)
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- The escape velocity from a massive object is the speed needed to reach an infinite distance from it and have just slowed to a stop, that is, to have just enough kinetic energy to climb out of the gravitational potential well and have none left. You can find the escape velocity by equating the total kinetic and gravitational potential energy to zero E = = muesc - GmM/r=0 Vesc = √2GM/r where G is Newton's constant of gravitation, M is the mass of the object from which the escape is happening, and r is its radius. This is physics you have seen in the first part of the course, and you should be able to use it to find an escape velocity from any planet or satellite. For the Earth, for example the escape velocity is about 11.2 km/s, and for the Moon it is 2.38 km/s. A very important point about escape velocity: it does not depend on what is escaping. A spaceship or a molecule must have this velocity or more away from the center of the planet to be free of its gravity, 1. In the atmosphere of…Assume your hair grows at a rate of 1/44th of an inch per day. How fast is that in nm/s (nanometers per second)? Given that a typical atom is on the order of 1 x 10^(-10) m in diameter (see Table 1.3 on page 18 of the textbook), at approximately what rate does the protein synthesis that assembles your hair strands deposit atoms in units of atoms per second? I need the second question to be rounded to 1 significant digit.The kinetic energy (T) of an object with mass m traveling at a speed v is defined as T = \frac{1}{2}mv^2T=21mv2. What is the kinetic energy (in J) of an object of mass 41 g traveling a velocity of 37 miles per hour? (1 mile = 1.609 km) Round your answer to the tenths (0.1) place.
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