What type of hypothesis test should be performed? Left-tailed z-testTwo-tailed t-testTwo-tailed z-testRight-tailed t-test p̂=p̂2=p̂=Test Statistic=p- value=Does sufficient evidence exist to support the claim that the level of support differs between the two cities at the a=0.05 signigicance level? (yes or no) A political campaign is interested in whether a geographic difference existed in support for raising the minimum wage in a certain state. Polls were conducted in the two largest cities in the state about raising the minimum wage. In city 1, a poll of 800 randomly selected voters found that 401 supported raising the minimum wage. In city 2, a poll of 1000 randomly selected voters found that 435 supported raising the minimum wage.What type of hypothesis test should be performed?\[\hat{p}_1 = \text{Ex: 0.123}\]\[\hat{p}_2 = \text{Ex: 0.123}\]\[\hat{p} = \text{Ex: 0.123}\]Test statistic = Ex: 0.12\( p \)-value = Ex: 0.123Does sufficient evidence exist to support the claim that the level of support differs between the two cities at the \( \alpha = 0.05 \) significance level?

Name: What type of hypothesis test should be performed? Left-tailed z-testTw
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: What type of hypothesis test should be performed? Left-tailed z-testTwo-tailed t-testTwo-tailed z-testRight-tailed t-test p̂=p̂2=p̂=Test Statistic=p- value=Does sufficient evidence exist to support the claim that the level of support differs between

Type of hypothesis test: The type of hypothesis test performed is two-tailed z test. Hypothesis: H0:p1-p2=0 H1:p1-p2≠0 Sample proportions: The sample proportion of voters who supported raising the minimum wage in city 1 can be calculated as follows: p1^=401800=0.501 The sample proportion of voters who supported raising the minimum wage in city 2 can be calculated as follows: p2^=4351000=0.435 The pooled sample proportion can be calculated as follows: p^=401+435800+1000=0.464Test statistic: z=p1^-p2^p^1-p^1n1+1n2=0.501-0.4350.4641-0.4641800+11000=0.0660.02366=2.79 P-value: The two tailed p-value can be calculated as follows: 2×Pz>2.79=2×1-Pz<2.79=2×1-0.9974=0.0052Decision rule: If p-value ≤ α, then reject the null hypothesis. Otherwise, fail to reject the null hypothesis. Conclusion: Here, p-value (=0.0052) is less than the significance level (0.05). Therefore, reject the null hypothesis. Thus, there is sufficient evidence to support the claim that the level of support differs between the two cities.