A point mass m =3 kg can move on a straight track from point A to point B. The points are on the parameter of a circular tableof radius R = 8.8 m which is rotating around its center counterclockwise at constant angular velocity w = 3 rad/s.ŷRBRRAt t = () the mass is at point A and begins to move at constant speed vo = 2 m/s to point B. Note that the speed remainsconstant during the process.What is the Coriolis force on the mass during its motion from point A to point B?a. 25.46*(Xr+Yr)O b. 50.91*(-Xr-Yr)O c. 36.00*(Xr-Yr)O d. 9.00*(-Xr+Yr)O e. 12.73*(Xr+Yr)Of. 36.00*(Xr+Yr)O g. 36.00*(-Xr+Yr)Oh. 25.46*(Xr-Yr)

Step 1:The coriolis force F is given byF=−2m(ω×v) or F=2m(v×ω)wherem is the mass of the objectω is…

Answered: A point mass m = 3 kg can move on a…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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R R A mass m = 88 kg slides on a frictionless track that has a drop, followed by a loop-the-loop with radius R = 15.8 m and finally a flat straight section at the same height as the center of the loop (15.8 m off the ground). Since the mass would not make it around the loop if released from the height of the top of the loop (do you know why?) it must be released above the top of the loop-the-loop height. (Assume the mass never leaves the smooth track at any point on its path.) 1) What is the minimum speed the block must have at the top of the loop to make it around the loop-the-loop without leaving the track? m/s Submit 2) What height above the ground must the mass begin to make it around the loop-the-loop? m Submit 3) If the mass has just enough speed to make around the loop without leaving the track, what will its speed be at the bottom of the loop? m/s Submit +
The center of the cylinder is moving to the left with constant velocity vo. Determine the angular velocity and the angular acceler- ation a of the bar. Neglect the thickness of the bar.
An Earth satellite has its apogee at 2750 km above the surface of Earth and perigee at 490 km above the surface of Earth. At apogee its speed is 830 m/s. What is its speed at perigee? Earth's radius is 6378 km (see below). A M Vp
A planet orbits its star in an elliptical orbit. Which of these quantities do not change as the planet orbits? O None of these quantities change as the planet orbits. O All of these quantities change as the planet orbits. O The planet's angular momentum O The planet's potential energy O The planet's kinetic energy
PLEASE SOME ANSWER THIS ASAP AND SHOW ALL THE WORK PLS A merry-go-round in a playground (spinning horizontal disk) of mass M and radius R is initially rotating inthe x/y plane at a constantω0around a fixed vertical axis through the middle of the disk. A girl of mass m runstowards italong a path that is tangent to the rim and then jumps on the rim and holds on. The disk spinsfasterafter she jumps on. Treat the girl as a point mass.a) Choose one: Which of the following is conserved for the disk+girl system before and after she jumps on? (i) mechanical energy, ii) angular momentum, iii) linear momentum. iv) 2 or more of the above. b) Draw an overhead sketch of the disk with the disk rotating such that ω0 is in the +z direction (out). Show thevelocity vector of thegirl right before she jumps on. Solve for the necessary speed v that she must have in order for the disk to tripleits angular velocity after she jumps on. Your expression should depend on ω0, m, M, andR. Simplify it as much as…
Asmall cube (M = 0.45 kg) is at a height of 315 cm up a frictionless track which has a loop of radius, R= 47.25 cm at the bottom. The %3D cube slides freely down the ramp and around the loop. Find the velocity of the block when it is at the top of the loop. V H R
Plz help.
Problem 2: A ball with mass mg at the end of a massless cord is swinging in a circle of radius R-1.09 m with and angular velocity e- Il rad's. Soler, Rachacl rsolertcnm.edu R Ctheespertta.com experta com - tracking id: IN7CC-FA-47-SSD6-37227, In sccondance with Expert TAY Terme Service cepying this information to any solutions tharing websine is strictly forbidden Doing sit may restult in lermination of your Expert TA Account. (art (a) Write an expression for the velocity v of the ball. Grade Summary Deductions Potential 100% 6. 4. 6. Submissions Attempts remaining: (4 per attempt) detailed view P. R Hint I give vpt Part (b) Calculate the velocity of the ball, v in m's. Part (e) In order to travel in a circle, the direction the balls path mus stantly be changing (curving inward). This constant change in direction towards the center of the circle is a center pointing acceleration called ceiltripetal acceleration ae. Write an expression for the centripetal acceleration ae of the ball, in…
Example: Visiting a jewelry store one evening, you hold a diamond up to the light of a sodium-vapor streetlamp. The heated sodium vapor emits yellow light with a frequency of 5.09 x 1014 Hz. Find the wavelength in vacuum (nvacum =1) and the wave speed and wavelength in diamond (ndiamond =2.419). Magnet Field Oscillation Given: Solution: (3 x 10° m/s) (1)(5.09 x 1014 Hz) nyacuum = 1 Vyacuum Ayacuum -= 5.89 x 10-7m ndamond =2.419 nf 3х 10* т/s (2.419) f = 5.09 x 1024 Hz Vdiamond = 1.24 x 10°m/s nf Vdiamond (1.24 x 10° m/s) Ayacuum = 2.44 x 10m 5.09 x 1014 Hz Activity: A 90.0-MHz radio wave (in the FM radio band) passes from vacuum into an insulating ferrite (a ferromagnetic material used in computer cables to suppress radio interference). Find the wavelength in vacuum and the wave speed and wavelength in the ferrite (nterrite =3.162). Use the rubrics as your guide in presenting your solution (refer to attachment A.2 at the next page).

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