R R A mass m = 88 kg slides on a frictionless track that has a drop, followed by a loop-the-loop with radius R = 15.8 m and finally a flat straight section at the same height as the center of the loop (15.8 m off the ground). Since the mass would not make it around the loop if released from the height of the top of the loop (do you know why?) it must be released above the top of the loop-the-loop height. (Assume the mass never leaves the smooth track at any point on its path.) 1) What is the minimum speed the block must have at the top of the loop to make it around the loop-the-loop without leaving the track? m/s Submit 2) What height above the ground must the mass begin to make it around the loop-the-loop? m Submit 3) If the mass has just enough speed to make it around the loop without leaving the track, what will its speed be at the bottom of the loop? m/s Submit +

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Chapter1: Units, Trigonometry. And Vectors
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A mass m = 88 kg slides on a frictionless track that has a drop, followed by
a loop-the-loop with radius R = 15.8 m and finally a flat straight section at
the same height as the center of the loop (15.8 m off the ground). Since
the mass would not make it around the loop if released from the height of
the top of the loop (do you know why?) it must be released above the top
of the loop-the-loop height. (Assume the mass never leaves the smooth
track at any point on its path.)
1) What is the minimum speed the block must have at the top of the loop
to make it around the loop-the-loop without leaving the track?
m/s Submit
2) What height above the ground must the mass begin to make it around
the loop-the-loop?
m Submit
3) If the mass has just enough speed to make around the loop without
leaving the track, what will its speed be at the bottom of the loop?
m/s Submit
+
Transcribed Image Text:R R A mass m = 88 kg slides on a frictionless track that has a drop, followed by a loop-the-loop with radius R = 15.8 m and finally a flat straight section at the same height as the center of the loop (15.8 m off the ground). Since the mass would not make it around the loop if released from the height of the top of the loop (do you know why?) it must be released above the top of the loop-the-loop height. (Assume the mass never leaves the smooth track at any point on its path.) 1) What is the minimum speed the block must have at the top of the loop to make it around the loop-the-loop without leaving the track? m/s Submit 2) What height above the ground must the mass begin to make it around the loop-the-loop? m Submit 3) If the mass has just enough speed to make around the loop without leaving the track, what will its speed be at the bottom of the loop? m/s Submit +
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