A 90.0-MHz radio wave (in the FM radio band) passes from vacuum into an insulatin in computer cables to suppress radio interference). Find the wavelength in vacuum the ferrite (nterrite =3.162). Use the rubrics as your guide in presenting your soluti page).
A 90.0-MHz radio wave (in the FM radio band) passes from vacuum into an insulatin in computer cables to suppress radio interference). Find the wavelength in vacuum the ferrite (nterrite =3.162). Use the rubrics as your guide in presenting your soluti page).
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter34: Electromagnetic Waves
Section: Chapter Questions
Problem 34.43P: A possible means of space flight is to place a perfectly reflecting aluminized sheet into orbit...
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Question
Transcribed Image Text:Example:
Visiting a jewelry store one evening, you hold a diamond up to the
light of a sodium-vapor streetlamp. The heated sodium vapor emits yellow light with a frequency of 5.09 x 1014
Hz. Find the wavelength in vacuum (nvacum =1) and the wave speed and wavelength in diamond (ndiamond =2.419).
Magnet Field Oscillation
Given:
Solution:
(3 x 10° m/s)
(1)(5.09 x 1014 Hz)
nyacuum = 1
Vyacuum
Ayacuum
-= 5.89 x 10-7m
ndamond =2.419
nf
3х 10* т/s
(2.419)
f = 5.09 x 1024 Hz
Vdiamond
= 1.24 x 10°m/s
nf
Vdiamond
(1.24 x 10° m/s)
Ayacuum
= 2.44 x 10m
5.09 x 1014 Hz
Activity:
A 90.0-MHz radio wave (in the FM radio band) passes from vacuum into an insulating ferrite (a ferromagnetic material used
in computer cables to suppress radio interference). Find the wavelength in vacuum and the wave speed and wavelength in
the ferrite (nterrite =3.162). Use the rubrics as your guide in presenting your solution (refer to attachment A.2 at the next
page).
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