A plot of 1/[A] versus time for the hypothetical reaction A →B+C yields a straight line. What is the order of the reaction? first-order second-order third-order O fourth-order b If it took 90. s for the concentration to drop 38 percent from its initial value of 0.50 M, what is the rate constant for the reaction? |L/(mol · s) Rate constant =
A plot of 1/[A] versus time for the hypothetical reaction A →B+C yields a straight line. What is the order of the reaction? first-order second-order third-order O fourth-order b If it took 90. s for the concentration to drop 38 percent from its initial value of 0.50 M, what is the rate constant for the reaction? |L/(mol · s) Rate constant =
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Reaction Order and Rate Constant Determination
#### (a) Reaction Order
A plot of \( \frac{1}{[\text{A}]} \) versus time for the hypothetical reaction:
\[ \text{A} \rightarrow \text{B} + \text{C} \]
yields a straight line. What is the order of the reaction?
- ○ first-order
- ● second-order ✔
- ○ third-order
- ○ fourth-order
The reaction is determined to be second-order because the plot of \( \frac{1}{[\text{A}]} \) versus time produces a straight line.
#### (b) Rate Constant Calculation
If it took 90.0 seconds for the concentration to drop 38 percent from its initial value of 0.50 M, what is the rate constant for the reaction?
Rate constant = \_\_\_\_ L/(mol·s)
Fill in the blank with the calculated rate constant value, using the information provided about the concentration change and time duration.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe19fa2ed-8566-4b3b-96d0-3591866fab62%2F5801808f-899a-4e9f-80dc-952d56417167%2F564fmm_processed.png&w=3840&q=75)
Transcribed Image Text:### Reaction Order and Rate Constant Determination
#### (a) Reaction Order
A plot of \( \frac{1}{[\text{A}]} \) versus time for the hypothetical reaction:
\[ \text{A} \rightarrow \text{B} + \text{C} \]
yields a straight line. What is the order of the reaction?
- ○ first-order
- ● second-order ✔
- ○ third-order
- ○ fourth-order
The reaction is determined to be second-order because the plot of \( \frac{1}{[\text{A}]} \) versus time produces a straight line.
#### (b) Rate Constant Calculation
If it took 90.0 seconds for the concentration to drop 38 percent from its initial value of 0.50 M, what is the rate constant for the reaction?
Rate constant = \_\_\_\_ L/(mol·s)
Fill in the blank with the calculated rate constant value, using the information provided about the concentration change and time duration.
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