3. The following reaction is observed to be second order with respect to NO and first order with respect to Br2. Br2 (g) + 2NO (g) → 2NOBr (g) a) Write the rate law for the observed reaction. 3 b) The following mechanisms have been proposed for the above reaction. Determine the rate law predicted by each mechanism. Circle the intermediate and determine the best mechanism that matches the observed rate law. Mechanism I Mechanism II Step 1: NO (g) + Br2 (g) 2 NOB12 (fast) Step 1: Br2 (g) + NO (g) → NOBR (g) + Br (g) (slow) k- k, Step 2: NOBr2 + NO → 2NOB (slow) Step 2: Br + NOBR → 2NOBr (fast)
3. The following reaction is observed to be second order with respect to NO and first order with respect to Br2. Br2 (g) + 2NO (g) → 2NOBr (g) a) Write the rate law for the observed reaction. 3 b) The following mechanisms have been proposed for the above reaction. Determine the rate law predicted by each mechanism. Circle the intermediate and determine the best mechanism that matches the observed rate law. Mechanism I Mechanism II Step 1: NO (g) + Br2 (g) 2 NOB12 (fast) Step 1: Br2 (g) + NO (g) → NOBR (g) + Br (g) (slow) k- k, Step 2: NOBr2 + NO → 2NOB (slow) Step 2: Br + NOBR → 2NOBr (fast)
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The following reaction is observed to be second order with respect to NO and first order with respect to Br2. Br2 (g) + 2NO (g) --> 2NOBr (g)
Transcribed Image Text:3. The following reaction is observed to be second order with respect to NO and first order with
respect to Br2.
Br2 (g) + 2NO (g) → 2NOB (g)
a) Write the rate law for the observed reaction.
3
b) The following mechanisms have been proposed for the above reaction. Determine the rate law
predicted by each mechanism. Circle the intermediate and determine the best mechanism that
matches the observed rate law.
Mechanism I
Mechanism II
k
Step 1: NO (g) + Br2 (g) 2 NOBR2 (fast)
k-1
Step 1: Br2 (g)+ NO (g) → NOB (g) + Br (g) (slow)
k,
Step 2: NOB12+ NO → 2NOB1 (slow)
Step 2: Br + NOBR → 2NOBr (fast)
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