The reaction between chlorine monoxide and nitrogen dioxide CIO(g) + NO₂(g) + M(g) → CIONO2(g) + M(g) produces chlorine nitrate (CIONO₂). A third molecule (M) takes part in the reaction but is unchanged by it (it remains "M" as a reactant and as a product). The reaction is first order in [CIO] and [NO₂]. What is the rate law of the reaction? Rate = k[CIO][NO₂][M] O Rate = k[CIONO₂] O Rate = = K[CIONO₂][M] O Rate = k[CIO][NO₂][M]* - O Rate = k[CIONO₂][M]* O Rate = k[CIO][NO₂] Indicate the reaction order with respect to M. O Zero order with respect to M O Impossible to determine the order with respect to M O First order with respect to M Hint: Knowing that the reaction is first order in both NO2 and CIO means that the exponent for the concentrations in the rate law for both of these reactants is 1. Because no dependence on the rate was given in the problem for M, we can assume that changing [M] does not affect the rate of the reaction.

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### Chemical Reaction Rate Law

**The reaction between chlorine monoxide and nitrogen dioxide:**

\[ \text{ClO}(g) + \text{NO}_2(g) + \text{M}(g) \rightarrow \text{ClONO}_2(g) + \text{M}(g) \]

This reaction produces chlorine nitrate (\( \text{ClONO}_2 \)). A third molecule (\( \text{M} \)) takes part in the reaction but remains unchanged (it appears as both a reactant and a product). The reaction is first order in \([\text{ClO}]\) and \([\text{NO}_2]\).

**Question:** What is the rate law of the reaction?

- \( \bigcirc \) Rate = \( k[\text{ClO}][\text{NO}_2][\text{M}] \)
- \( \bigcirc \) Rate = \( k[\text{ClONO}_2] \)
- \( \bullet \) Rate = \( k[\text{ClONO}_2][\text{M}] \)
- \( \bigcirc \) Rate = \( k[\text{ClO}][\text{NO}_2][\text{M}]^2 \)
- \( \bigcirc \) Rate = \( k[\text{ClONO}_2][\text{M}]^{1.5} \)
- \( \bigcirc \) Rate = \( k[\text{ClO}][\text{NO}_2] \)

**Indicate the reaction order with respect to \( \text{M} \):**

- \( \bigcirc \) Zero order with respect to \( \text{M} \)
- \( \bullet \) Impossible to determine the order with respect to \( \text{M} \)
- \( \bigcirc \) First order with respect to \( \text{M} \)

**Hint:** Knowing that the reaction is first order in both \([\text{NO}_2]\) and \([\text{ClO}]\) means that the exponent for the concentrations in the rate law for both of these reactants is 1. Because no dependence on the rate was given in the problem for \( \text{M} \), we can assume that changing \([\text{M}]\) does not affect the rate of the reaction.

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Transcribed Image Text:### Chemical Reaction Rate Law **The reaction between chlorine monoxide and nitrogen dioxide:** \[ \text{ClO}(g) + \text{NO}_2(g) + \text{M}(g) \rightarrow \text{ClONO}_2(g) + \text{M}(g) \] This reaction produces chlorine nitrate (\( \text{ClONO}_2 \)). A third molecule (\( \text{M} \)) takes part in the reaction but remains unchanged (it appears as both a reactant and a product). The reaction is first order in \([\text{ClO}]\) and \([\text{NO}_2]\). **Question:** What is the rate law of the reaction? - \( \bigcirc \) Rate = \( k[\text{ClO}][\text{NO}_2][\text{M}] \) - \( \bigcirc \) Rate = \( k[\text{ClONO}_2] \) - \( \bullet \) Rate = \( k[\text{ClONO}_2][\text{M}] \) - \( \bigcirc \) Rate = \( k[\text{ClO}][\text{NO}_2][\text{M}]^2 \) - \( \bigcirc \) Rate = \( k[\text{ClONO}_2][\text{M}]^{1.5} \) - \( \bigcirc \) Rate = \( k[\text{ClO}][\text{NO}_2] \) **Indicate the reaction order with respect to \( \text{M} \):** - \( \bigcirc \) Zero order with respect to \( \text{M} \) - \( \bullet \) Impossible to determine the order with respect to \( \text{M} \) - \( \bigcirc \) First order with respect to \( \text{M} \) **Hint:** Knowing that the reaction is first order in both \([\text{NO}_2]\) and \([\text{ClO}]\) means that the exponent for the concentrations in the rate law for both of these reactants is 1. Because no dependence on the rate was given in the problem for \( \text{M} \), we can assume that changing \([\text{M}]\) does not affect the rate of the reaction. --- **Submit Button:** -
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