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A planetary nebula expanded in radius 0.2 arc seconds in 10 years. Doppler measurements show the nebula is expanding at a rate of 25 km/s. How far away is the nebula in parsecs? If the nebula now has a radius of 9 arc minutes, how long ago (in years) did the star explode? Part 1 of 3 We first need to determine what distance (in pc) the nebula expanded in parsecs during the time mentioned. Ad = V pc/s¹s So we first need to convert the rate into pc/s and the time into seconds: 1 pc Vpc/s = Vkm/s 3.09 x 10¹3 km 8.09e-13 pc/s (Tyr)(365 days/yr) (24 hrs/day)(3600 s/hr) 3.1536e8 3.15e+08 s pc/s = 8.09e-13 Ts Ts Ad = V pc Ad pc pc/s's = 2.551e-4 Part 2 of 3 Now we can use the small angle formula to calculate the distance (in pc). 2.06 x 105 D = 262.75 D = Ad- 0 0.000255 pc as 263 pc

A planetary nebula expanded in radius 0.2 arc seconds in 10 years. Doppler measurements show the nebula is expanding at a rate of 25 km/s. How far away is the nebula in parsecs? If the nebula now has a radius of 9 arc minutes, how long ago (in years) did the star explode? Part 1 of 3 We first need to determine what distance (in pc) the nebula expanded in parsecs during the time mentioned. Ad = V pc/s¹s So we first need to convert the rate into pc/s and the time into seconds: 1 pc Vpc/s = Vkm/s 3.09 x 10¹3 km 8.09e-13 pc/s (Tyr)(365 days/yr) (24 hrs/day)(3600 s/hr) 3.1536e8 3.15e+08 s pc/s = 8.09e-13 Ts Ts Ad = V pc Ad pc pc/s's = 2.551e-4 Part 2 of 3 Now we can use the small angle formula to calculate the distance (in pc). 2.06 x 105 D = 262.75 D = Ad- 0 0.000255 pc as 263 pc

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A planetary nebula expanded in radius 0.2 arc seconds in 10 years. Doppler measurements show the nebula is expanding at a rate of 25 km/s. How far away is the nebula in parsecs? If the nebula now has a radius of 9 arc minutes, how long ago (in years) did the star explode? Part 1 of 3 We first need to determine what distance (in pc) the nebula expanded in parsecs during the time mentioned. Ad = V pc/s¹s So we first need to convert the rate into pc/s and the time into seconds: 1 pc Vpc/s = Vkm/s 3.09 x 10¹3 km 8.09e-13 pc/s (Tyr)(365 days/yr) (24 hrs/day)(3600 s/hr) 3.1536e8 3.15e+08 s pc/s = 8.09e-13 Ts Ts Ad = V pc Ad pc pc/s's = 2.551e-4 Part 2 of 3 Now we can use the small angle formula to calculate the distance (in pc). 2.06 x 105 D = 262.75 D = Ad- 0 0.000255 pc as 263 pc
Transcribed Image Text:A planetary nebula expanded in radius 0.2 arc seconds in 10 years. Doppler measurements show the nebula is expanding at a rate of 25 km/s. How far away is the nebula in parsecs? If the nebula now has a radius of 9 arc minutes, how long ago (in years) did the star explode? Part 1 of 3 We first need to determine what distance (in pc) the nebula expanded in parsecs during the time mentioned. Ad = V pc/s¹s So we first need to convert the rate into pc/s and the time into seconds: 1 pc Vpc/s = Vkm/s 3.09 x 10¹3 km 8.09e-13 pc/s (Tyr)(365 days/yr) (24 hrs/day)(3600 s/hr) 3.1536e8 3.15e+08 s pc/s = 8.09e-13 Ts Ts Ad = V pc Ad pc pc/s's = 2.551e-4 Part 2 of 3 Now we can use the small angle formula to calculate the distance (in pc). 2.06 x 105 D = 262.75 D = Ad- 0 0.000255 pc as 263 pc
Part 3 of 3 To find out how long ago the star exploded, we first need to use the small angle formula to determine the radius of nebula in parsecs. (,) (60 arc seconds/arc minute) 2.06 x 105 d, = ts Then we can see how long it's been expanding, which tells us when the star exploded. (Enter your answer in seconds then in years.) dr Vpc/s = d₁ = D₁ t = t. t = рс = S 1 yr ´s (3600 s/hr) (24 hr/day) (365 days) years
Transcribed Image Text:Part 3 of 3 To find out how long ago the star exploded, we first need to use the small angle formula to determine the radius of nebula in parsecs. (,) (60 arc seconds/arc minute) 2.06 x 105 d, = ts Then we can see how long it's been expanding, which tells us when the star exploded. (Enter your answer in seconds then in years.) dr Vpc/s = d₁ = D₁ t = t. t = рс = S 1 yr ´s (3600 s/hr) (24 hr/day) (365 days) years
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