Static Friction Force Revisited Now let's go back and consider the static situation again. Let the angle 0 be the angle you calculated in the first part of this problem, Oslip. To keep the block from slipping, you apply a horizontal (parallel to the surface of Earth) force directed to the right on the block. Your horizontal force Fyb has a magnitude of 57 N. Calculate the magnitude and direction of the force due to static friction for this new situation, assuming that the block does not slip. Enter a magnitude for this part, but consider what the sign of your answer tells you about the direction of the force. Click here for a hint fs,rb 59.196 N ||
Static Friction Force Revisited Now let's go back and consider the static situation again. Let the angle 0 be the angle you calculated in the first part of this problem, Oslip. To keep the block from slipping, you apply a horizontal (parallel to the surface of Earth) force directed to the right on the block. Your horizontal force Fyb has a magnitude of 57 N. Calculate the magnitude and direction of the force due to static friction for this new situation, assuming that the block does not slip. Enter a magnitude for this part, but consider what the sign of your answer tells you about the direction of the force. Click here for a hint fs,rb 59.196 N ||
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I am pretty sure that this can be solved by adding 57 to mg cos(theta) but when I enter -59.196 into the problem it says that it is incorrect.

Transcribed Image Text:Static Friction Force Revisited
Now let's go back and consider the static situation again. Let the angle 0 be the angle you calculated in the first part of this
problem, Oslip. To keep the block from slipping, you apply a horizontal (parallel to the surface of Earth) force directed to the right
on the block. Your horizontal force Fyb has a magnitude of 57 N. Calculate the magnitude and direction of the force due to static
friction for this new situation, assuming that the block does not slip. Enter a magnitude for this part, but consider what the sign of
your answer tells you about the direction of the force.
Click here for a hint
fs,rb
59.196 N

Transcribed Image Text:A block is resting on a ramp as shown in the figure below. You can change the inclination angle 0 by raising one end of the ramp. The
block has a mass mp =
10 kg. At the interface between the ramp and the block, the coefficient of static friction is us = 0.4, and the
coefficient of kinetic friction is uk = 0.28.
d
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