A piece of thin uniform wire of mass M = 6.9 kg and length b = 3 m is bent into an equilateral triangle. In terms of M and b, find the moment of inertia of the wire triangle about an axis perpendicular to the plane of the triangle and passing through one of its vertices. [Hint: This problem isn't too difficult, but it does require a few carefully- executed steps. Each of the three sides make individual contributions to the moment of inertia. For two of the sides, the contribution is straightforward. For the third side, you'll want to use the parallel-axis theorem and the fact that the equilateral triangle's height is h = = ³d where d is the length of one side. That height is equal to the distance from the axis to the center of the third side.] = kg. m² Record your numerical answer below, assuming three significant figures. Remember to include a "-" as necessary.

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Algebraic manipulation.
A piece of thin uniform wire of mass M = 6.9 kg and length b = 3 m is bent
into an equilateral triangle. In terms of M and b, find the moment of
inertia of the wire triangle about an axis perpendicular to the plane of the
triangle and passing through one of its vertices.
[Hint: This problem isn't too difficult, but it does require a few carefully-
executed steps. Each of the three sides make individual contributions to
the moment of inertia. For two of the sides, the contribution is
straightforward. For the third side, you'll want to use the parallel-axis
√3
theorem and the fact that the equilateral triangle's height is h
where d is the length of one side. That height is equal to the distance from
the axis to the center of the third side.]
2
I =
kg - m²
Record your numerical answer below, assuming three significant figures.
Remember to include a "-" as necessary.
Transcribed Image Text:Algebraic manipulation. A piece of thin uniform wire of mass M = 6.9 kg and length b = 3 m is bent into an equilateral triangle. In terms of M and b, find the moment of inertia of the wire triangle about an axis perpendicular to the plane of the triangle and passing through one of its vertices. [Hint: This problem isn't too difficult, but it does require a few carefully- executed steps. Each of the three sides make individual contributions to the moment of inertia. For two of the sides, the contribution is straightforward. For the third side, you'll want to use the parallel-axis √3 theorem and the fact that the equilateral triangle's height is h where d is the length of one side. That height is equal to the distance from the axis to the center of the third side.] 2 I = kg - m² Record your numerical answer below, assuming three significant figures. Remember to include a "-" as necessary.
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