A solid sphere of uniform density has a mass of 2.42 kg and a radius of 0.432 meters. A force of 13.2 Newtons is applied tangentially to the equator of the sphere. If the sphere is free to rotate without friction about an axis perpendicular to the equator to which the 13.2 Newton force is applied, what is the angular acceleration α of the sphere caused by the applied force? It may be useful to bear in mind that the moment of inertia I for a solid sphere of uniform density is I = (2/5)MR^2 where M is the mass of the sphere and R is the radius of the sphere. Also, bear in mind in this case that the torque τ is τ = RF since the force F is applied tangentially to the equator. A. 15.3 rad/s^2 B. 31.5 rad/s^2 C. 50.3 rad/s^2 D. 68.5 rad/s^2
A solid sphere of uniform density has a mass of 2.42 kg and a radius of 0.432 meters. A force of 13.2 Newtons is applied tangentially to the equator of the sphere. If the sphere is free to rotate without friction about an axis perpendicular to the equator to which the 13.2 Newton force is applied, what is the angular acceleration α of the sphere caused by the applied force? It may be useful to bear in mind that the moment of inertia I for a solid sphere of uniform density is I = (2/5)MR^2 where M is the mass of the sphere and R is the radius of the sphere. Also, bear in mind in this case that the torque τ is τ = RF since the force F is applied tangentially to the equator. A. 15.3 rad/s^2 B. 31.5 rad/s^2 C. 50.3 rad/s^2 D. 68.5 rad/s^2
A solid sphere of uniform density has a mass of 2.42 kg and a radius of 0.432 meters. A force of 13.2 Newtons is applied tangentially to the equator of the sphere. If the sphere is free to rotate without friction about an axis perpendicular to the equator to which the 13.2 Newton force is applied, what is the angular acceleration α of the sphere caused by the applied force? It may be useful to bear in mind that the moment of inertia I for a solid sphere of uniform density is I = (2/5)MR^2 where M is the mass of the sphere and R is the radius of the sphere. Also, bear in mind in this case that the torque τ is τ = RF since the force F is applied tangentially to the equator. A. 15.3 rad/s^2 B. 31.5 rad/s^2 C. 50.3 rad/s^2 D. 68.5 rad/s^2
A solid sphere of uniform density has a mass of 2.42 kg and a radius of 0.432 meters. A force of 13.2 Newtons is applied tangentially to the equator of the sphere. If the sphere is free to rotate without friction about an axis perpendicular to the equator to which the 13.2 Newton force is applied, what is the angular acceleration α of the sphere caused by the applied force? It may be useful to bear in mind that the moment of inertia I for a solid sphere of uniform density is I = (2/5)MR^2 where M is the mass of the sphere and R is the radius of the sphere. Also, bear in mind in this case that the torque τ is τ = RF since the force F is applied tangentially to the equator.
A. 15.3 rad/s^2 B. 31.5 rad/s^2 C. 50.3 rad/s^2 D. 68.5 rad/s^2
Definition Definition Rate of change of angular velocity. Angular acceleration indicates how fast the angular velocity changes over time. It is a vector quantity and has both magnitude and direction. Magnitude is represented by the length of the vector and direction is represented by the right-hand thumb rule. An angular acceleration vector will be always perpendicular to the plane of rotation. Angular acceleration is generally denoted by the Greek letter α and its SI unit is rad/s 2 .
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