A particle with a charge of -5 μC enters the region of a uniform electric field of magnitude E that point upwards (see animation). The particle enters the field halfway between two horizontal parallel plates that are 5.0 cm apart with a horizontal initial velocity of 5 x 105 m/s. The mass of the particle is 2.0 x 10-16 kg. Find: a. The magnitude of the electric field so that the particle can travel 60 ns inside the field before hitting one of the plates. b. The horizontal distance the particle travels before hitting one of the plates.

icon
Related questions
Question

A particle with a charge of -5 μC enters the region of a uniform electric field of magnitude E that
point upwards (see animation). The particle enters the field halfway between two horizontal
parallel plates that are 5.0 cm apart with a horizontal initial velocity of 5 x 105 m/s. The mass of
the particle is 2.0 x 10-16 kg. Find:
a. The magnitude of the electric field so that the particle can travel 60 ns inside the field
before hitting one of the plates.
b. The horizontal distance the particle travels before hitting one of the plates. 

Expert Solution
Step 1

Given that,

m=2×10-6 kgq=-5 μC, t=60×10-9 sv=5×105 m/sd=5×10-2 m

Advanced Physics homework question answer, step 1, image 1

When charged particle is an electric field then the force acting on the charge particle is given as

F=qE

where q is the magnitude of the charge and E is the electric field. Also since we know that,

F=ma

Therefore from the above two equation the acceleration on the charge particle can be written as

a=qEm

trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 1 images

Blurred answer