Two charges one negative and one positive with strength Q1 3.6m apart. P is located x distance from Q1, and is a point where the sum of the voltage of the two charges will sum to zero. What is the magnitude and direction in x-axis of the electric field at point P due to Q1 and Q2 in units of Newton/Coulomb? = -3*q and Q2= +2*q (where q=7.0 nC,q=7.0*10-ºC) are placed
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- The figure shows an electric dipole. What is the magnitude of the dipole's electric field at point P? Assume that q = 2.53 x 10-6 C, d= 5.80 x 10-6 m, and r = 0.398 cm. d/2 d/2 Number Units N/C or V/mThe figure shows an electric dipole. What is the magnitude of the dipole's electric field at point P? Assume that q = 9.11 × 10° C, d = 6.31 x 106 m, and r = 6.21 cm. L. +9+ d/2 F d/2The figure shows an electric dipole. What is the magnitude of the dipole's electric field at point P? Assume that q = 6.44 × 10-6 C, d = 4.45 × 10-6 m, and r = 0.150 cm.
- Consider two oppositely charged, parallel metal plates. The plates are square with sides of 58 cm and carry charges 74 μC and -74 μC. What is the magnitude of the electric field (in N/C) in the region between the plates?A proton and an electron are moving due east in a constant electric field that also points due east. The electric field has a magnitude of 3.0 x 104 N/C. Determine the magnitude of the acceleration of the proton and the electron. = ap :! de MIA +2 µC charge is at the origin. A +5 µC charge is on the x-axis at +1.0 m. At what point between the charges is the electric field zero? +10 cm +18 cm +39 cm +45 cm
- The plates of a parallel plate capacitor are 3.28mm apart, and have an area of 12.2cm². Each plate carries a charge of magnitude 4.35x10–³ C. The plates are in vacuum. What is the magnitude of electric field between the plates?Three charged particles are placed at the corners of an equilateral triangle of side 1.20 mm (see (Figure 1)). The charges are Q1Q1 = 7.4 μCμC , Q2Q2 = -7.8 μCμC , and Q3Q3 = -5.0 μCμC .The point charges in the figure below are located at the corners of an equilateral triangle 25.0 cm on a side, where qp = +13.0 µC and g. -6.75 µC. (Assume that the +x-axis is directed to the right.) la (a) Find the electric field at the location of qa. magnitude N/C 60 direction In what direction does an electric field that is created by a negative charge point?° (counterclockwise from the +x-axis) (b) What is the force on ga, given that qa = +1.50 nC? magnitude N 59.98 What sides of the triangle are given by the electric field in the x and y directions?° (counterclockwise from the +x-axis) direction
- An electron initially at rest is released in a uniform electric field, the electron is accelerated horizontally to the right, traveling 4.77 m in the first 3.24x10-6s after being released, what is the magnitude of the electric field? electron q: 1.602x10-19 c m: 9.11x10-31 kg. Ans in N/CAn electron flies into a constant electric field (along the direction of the lines of E-field). The initial electron velocity is 10 km/s. Calculate the magnitude the electric field if the electron stops in 6 nsec. The electron mass is me =9.11×10-31 kg, the electron charge is qe = -1.61×10-19 C. The electric field, E = Units .mh.2